How the Concentration of the Substrate Affects the Reaction in the Catalase Inside Potato Cells

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How the Concentration of the Substrate Affects the Reaction in the Catalase Inside Potato Cells Introduction Enzymes are made of proteins and they speed up reactions, this means that they act as catalysts. Hydrogen peroxide is a byproduct of our cell's activities and is very toxic. The enzymes in our bodies break down the hydrogen peroxide at certain temperatures they work best at body temperature, which is approximately 37 degrees. At high temperatures, the cells begin to denature. This means that the hydrogen peroxide is prevented from being broken down because they will not 'fit' into the enzyme.[IMAGE] Objective I am going to find out how the concentration of the substrate, hydrogen peroxide affects the reaction in the catalase inside the potato cells. I shall be measuring how much gas is given off. This will be done by measuring the amount of froth on the surface of the liquid. The oxygen released is collected in the form of these bubbles. The equation for the reaction is: (catalase) [IMAGE] H2O2 2H2O + O2 (hydrogen peroxide) (2 part water) (oxygen) I will change the concentration of H2O2 and O2 (making sure the volume stay the same, when one part of a H2O2 particle is taken, an O2 particle is added. Prediction As the levels of H2O2 increase, gas is produced faster and in a greater quantity. This means that the height of the froth will increase. The froth is produced due to the gas as it bubbles from the potato slice. This gas is given off as a waste product from the reaction where H2O2 (substrate) breaks down the enzymes in the potato. If I were to roughly plot a graph for the reaction, it would look like this, [IMAGE] The graph shows that as the concentration of hydrogen peroxide is increased the more oxygen is given off. This is because there is more hydrogen peroxide to be broken down by the enzyme and with more hydrogen peroxide in the reaction, more oxygen is released.

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