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Investigation of electrolysis
Report on electrolysis
Report on electrolysis
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INTRODUCTION: In this experiment I will be investigating how the
amount of copper affects the mass of the cathode. I will do this
experiment twice so that I have an average of my results so that they
are accurate. I have already done my preliminary work and from it, I
have noticed that I will have to make some changes with the method of
my experiment.
AIM: In this experiment, I intend to find out how much copper in the
solution affects the mass of the cathode. I will be observing to see
what is happening and exactly how much copper is being deposited on
the cathode. Out of the four variables that are listed below, I will
be concentrating on the time the electrodes are left in the solution
and the size of current that will be applied in this experiment.
VARIABLES: There are four variables, which affect this investigation.
The first variable is the size of the current applied in the solution.
As the current raises so does amount of electrons that are produced on
the cathode. This means the anode loses its positively charged ions,
which the cathode gains, which means more positive ions, will combine
with the electrons on the cathode to produce copper.
The second variable that affects the experiment is the amount of time
the experiment is carried out for. The greater the time the electrodes
are left in the solution, the more time there is for the copper to be
gathered at the anode.
The third variable that affects the experiment is the temperature of
the copper II sulphate solution. As the temperature of the solution
increases, more of the ions gain kinetic energy and begin to move
faster. This enables the positive and negative charged ions to collide
faster with the electrodes. As more of the positive and negative ions
collide, there is a greater chance for the pure copper to be formed at
the cathode.
The fourth variable the affects the experiment is the size of the
Lab 4: Energy Conservation: Hot Stuff!! The purpose of this experiment is to try to find the original temperature of the hot water in the heater using the 60 degrees C thermometer. Use your 60°C thermometer, and any materials available in your laboratory, to determine the temperature of the water in the coffee pot. During this experiment we calculated the original temperature of a heater after it had been cooled down, and we did this by measuring hot, cold, and warm water, with a thermometer that had tape covering 60 degrees and up.
Figure 1 shows the minimum, maximum and average length of time it took for each solution to be depleted of oxygen. The scatter in the values suggests the presence of random errors.
· I made sure I put the same amount of water in the copper can.
the system. At a water/ air interface, the head group is buried in the solution while the tail group
Electrolysis is the only permanent hair removal methods that can help you achieve and maintain a smooth, hair-free beautiful aspects. This is a convenient, low-Charge strategy to refresh your image, increase your confidence and enhance Your enjoyment of life everyday.
The final weight of our Cu was 1.12g we calculated out that if we had 0.0157 moles of Cu we would have ended up with 1.00g of Cu we got 1.12g so what we suspect to have happened is that we got 48% 2CuO which with 0.0157 moles of it we would have had 1.25g of it. By the look of our copper we can assume we got 48% 2CuO which should have resulted in 0.60g of it. Pairing that with a 52% Cu we should have gotten 0.52g of it added together they equal 1.12g that is exactly we got in the end.
To investigate the temperature change in a displacement reaction between Copper Sulphate Solution and Zinc Powder
Obtain a sample of metal that has been immersed in boiling water and place it in the cup of water.
of Copper Sulphate. To do this I plan to work out the amount of water
By analysing the results it could be seen that there was a relationship between the concentration of sodium thiosulfate and the time take for the cross to be no longer visible on the white tile through the solution. From graph 1 it could be seen that the concentration of sodium thiosulfate and the time taken for the reaction to be completed are inversely proportional, as when the concentration of sodium thiosulfate increases, the time taken decreases and the graph levels out as it approached the x-axis. Graph 2 supports this by showing that the concentration of sodium thiosulfate and the rate of the reaction share a linear relationship, meaning that the concentration is directly proportional to the inverse of the time taken.
Equipment Potato, Borer, Beakers, Measuring Cylinder, Stopclocks, Distilled Water, Electronic Balance, Salt solutions of various concentrations. Diagram [IMAGE] [IMAGE] [IMAGE] When we leave the potato in the solution for the allocated time, water
Electroplating Experiment Aim To find the amount copper gains or loses on the electrodes using different amounts of current each time during electrolysis. How the changing of current affects the electroplating of copper. Introduction Electroplating is generally carried out in order to improve the appearance or corrosion resistance of the surface of a metal by electrodepositing a thin layer of metal ion on it. The metal substrate to be coated is made by the cathode in an electrolytic cell. The cell used in electroplating contains an electrolyte which is usually an aqueous solution containing a reasonably high concentration of an ion of the metal which is to be electroplated on the surface.
However, when the pH levels reach a certain stage, the iron can then precipitate out, coating sediments with the characteristic yellow, red or orange colourings (D.E.P. 2, 2002; U.S.G.S. ; U.S.E.P.A., 2002). The rate that A.M.D. advances is also influenced by the presence of certain bacteria (Doyle; U.S.G.S). A.M.D. that has dissolved heavy metals such as copper, lead and mercury can contaminate ground and surface water.
Electrolysis Investigation Planning In this investigation, I will assess how changing the electric current in the electrolysis of acidified water affects the rate at which hydrogen gas is produced. The solution to be electrolysed is made up using acid and water. It is of little consequence what acid is used however in this case I will use Sulphuric acid (H2SO4). When H2SO4 is put in water it is dissociated and forms ions: H2SO4 → 2H (2+) + SO4 (2-) Ions are also present from the water in the solution: H2O → H (+) + OH (-) During the electrolysis process, the positive hydrogen ions move towards the cathode and the negative hydroxide and sulphate ions move towards the anode.