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Enzymes and their importance
Functions of enzymes in medicine and industries
Functions of enzymes in medicine and industries
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Diffusion is the movement of a substance from an area with a high concentration to an area that is less concentrated (Houtman, A., et .al.,2015). However, osmosis is a special type of diffusion where water moves across a semi-permeable membrane. Understanding enzymatic activity is important when analysing the breakdown of sucrose. Enzymes are important when it comes to the function of cells. Enzymes are protein molecules that have the ability to speed up chemical reactions (Houtman, A., et.al., 2015). Invertase is an enzyme that breaks down sucrose into fructose and glucose (WOU Biology, 2018). When the large sucrose molecule is broken down into fructose and glucose, they become small enough to move through semi-permeable membranes. My hypothesis is if we put invertase in a solution with sucrose, it will catabolize it, and the glucose will diffuse across the membrane so we should get less of a rise in the osmometer. I predict that the solution that has more of a rise in the osmometer will be the one with just sucrose, the green solution.
Thorough analysis of the graph displayed enough evidence suggesting that an increase in substrate concentration will increase the height of bubbles until it reaches the optimum amount of substrate concentration, resulting in a plateau in the graphs (figure 2). Hence; supported the hypothesis.
Enzymes are proteins that increase the rate of chemical reaction by lowering their activation energy. The enzyme glucose oxidase is one of the most widely used enzyme as an analytical reagent due to its ability to identify the presence of glucose, its low cost and good stability. This report discusses the role of enzymes concentration in biological reactions and the catalytic activity of glucose oxidase on D-Glucose. The activity was studied by spectrophotometry and the results were first tabulated and then plotted. The results of this experiment indicate that the enzyme concentration has no major affect on the rate of
Carbohydrate digestion begins in the saliva and stomach where alpha-amylase hydrolyses alpha-1, 4 glycosidic bonds between glucose molecules in starch, forming maltotriose, the disaccharide maltose and dextrin’s made of five to ten glucose molecules (Lim, 2007). The disaccharides sucrose and lactose come directly from food. There are four enzymes found on the brush-border membrane responsible for hydrolysing sucrose, lactose and the products of starch break down, into monosaccharaides so that they can be absorbed (Lieberman et al, 2007). These enzymes are known as glycosidases and include; glucoamylase, lactase, trehalase and sucrase isomaltase (Lieberman et al, 2007). Sucrase isomaltase...
The Effect of Solute Concentration on the Rate of Osmosis Aim: To test and observe how the concentration gradient between a potato and water & sugar solution will affect the rate of osmosis. Introduction: Osmosis is defined as, diffusion, or net movement, of free water molecules from high to low concentration through a semi-permeable membrane. When a substance, such as sugar (which we will be using in the experiment we are about to analyse), dissolves in water, it attracts free water molecules to itself, and in doing so, stops them from moving freely. The effect of this, is that the concentration of (free) water molecules in that environment goes down. There are less free water molecules, and therefore less water molecules to pass across a semi-permeable membrane, through which sugar molecules and other molecules attached to them are too big to diffuse across with ease.
Glucose is liberated from dietary carbohydrate such as starch or sucrose by hydrolysis within the
The experiment is aimed at giving a better understatement of osmosis process and the different conditions in which osmosis occurs.
If the concentration of sucrose increases, then the mass of the potato will decrease. However, if the concentration of the solution in the beaker is less than that of the potato (such as distilled water), then the mass of the potato will increase. So, as the concentration of sucrose increases the rate of osmosis increases.
However not in sucrose, the RBCs were semi-permeable. RBCs diffuse in the water around five minutes, but in glycerol RBCs diffuse in fifteen minutes. Several factors are involved that affect the rate at which the RBCs diffuse, could have been because of the size, polarity, or the charge of the molecule. Urea is the carbonic acid found in urine, blood, and lymph; it is formed in the liver from amino acids and ammonia. It is important that urea is permeable because the amount of urea in the body is essential because it helps undergo waste product. Glycerol is combination of sugar and alcohol. This solution is an important component for storage of fats that are ingested into the body as food, this one good reason why glycerol is permeable. Sucrose however has low permeability which is why sucrose has a slow rate of diffusion and glycerol and urea on the other hand has fast rates of
The sugar molecule lactose is found in dairy products and people with Lactose Intolerance are unable to digest lactose because the enzyme lactase is unable to split the sugar molecule into glucose. Lactase is an enzyme that breaks lactose down into galactose and glucose. Lactase functions best between 21 and 48 degrees Celsius (or 70 and 120 degrees Fahrenheit). Cooler temperatures will slow down lactase’s function, whereas high temperatures can denature it or lactase will lose its shape. If lactase is rendered nonfunctional because of temperature or pH extremes, the breakdown of lactose stops. Lactose intolerance occurs when this breakdown fails due to insufficient or ineffective lactase. The experiment will stimulate the process
Abstract: Enzymes are catalysts therefore we can state that they work to start a reaction or speed it up. The chemical transformed due to the enzyme (catalase) is known as the substrate. In this lab the chemical used was hydrogen peroxide because it can be broken down by catalase. The substrate in this lab would be hydrogen peroxide and the enzymes used will be catalase which is found in both potatoes and liver. This substrate will fill the active sites on the enzyme and the reaction will vary based on the concentration of both and the different factors in the experiment. Students placed either liver or potatoes in test tubes with the substrate and observed them at different temperatures as well as with different concentrations of the substrate. Upon reviewing observations, it can be concluded that liver contains the greater amount of catalase as its rates of reaction were greater than that of the potato.
Investigation of the Concentration and the Effect of Sucrose on Osmosis in Apple and Potato Tissues
Osmosis in Potato Tubes Osmosis: Osmosis is the movement of water molecules through a semi-permeable membrane from a high concentration to a low concentration. Diagram: [IMAGE] [IMAGE] Aim: To see the effects of different concentration of sugar solution on Osmosis in potato tubes. Key factor: In the investigation we change the sugar solution from: 0%-10%-20%-30%-40%-50% this is the independent variable; the dependant variable is the change in mass. Prediction: I predict that all the potato tubes in pure water or low concentration sugar solution will swell because water enters their cells by osmosis.
...remain the same at 4ºC and 25ºC. The final result of this experiment was that glucose was more present in environments of higher temperatures. Our hypothesis and predictions were wrong because lower temperatures do not break down the enzymes because they become denatured. The enzyme activity decreases once the temperature decreases, as well. Enzyme activity increases when there is a rise in temperature, which is why lactose is broken down in much higher temperatures, resulting in a high presence of glucose.
Molisch test is one of the useful qualitative test for presence of carbohydrates in solution. The three glucose solutions all have a violet colored ring formed at the junction between the two layers. This showed that carbohydrates are present in these sugar solution. This test involved the addition of concentrated sulphuric acid which causes dehydration of all carbohydrates to give ‘furfural’ compound, where pentoses are dehydrated to furfural, and hexoses are dehydrated to 5-hydroxymethylfurfural (Molish's reagent, 2009). These compounds will later react with – naphtol which is Molisch reagent to give a purple colored complex. The test has to be carried out slowly as the violet colour formed at the surface of contact of concentrated sulfuric
Without enzymes, reactions wouldn’t occur and living organisms would die. For instance, the enzyme in the stomach breaks down large molecules to smaller molecules to absorb nutrition faster. Researchers experimented with enzyme activity with a potato extract. Researchers will test enzyme activity by increasing and decreasing pH levels, lowering and increasing temperature, and substrate concentration effects. In the first experiment, researchers hypothesized whether different pH levels would change how much Benzoquinone are created and how will the enzymes function in neutral pH levels than higher and lower levels. Researchers used potato extract and different levels of pH to test their hypothesis. In addition, researchers questioned at what temperature does the greatest amount of potato extract enzyme activity take place in. Researchers then hypothesized that the results would indicate the greatest amount of potato enzyme activity level will take place in room temperature. In this experiment, researchers used potato extract and different temperature levels to test the hypothesis. Moreover, researchers wanted to test the color intensity scale and how specific catechol oxidase is for catechol. In this experiment, researchers used dH2O, catechol solution, hydroquinone, and potato extract. Lastly, researchers tested the substrate concentration and how it has an effect on enzyme activity. In this experiment researchers used different measurements of catechol and 1cm of potato extract. Researchers hypothesized that the increase o substrate would level out the enzyme activity