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factors affecting the resistance of a wire
factors affecting the resistance of a wire
factors affecting the resistance of a wire
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Measuring the Resistivity of a Wire
Aim
The aim of this experiment is to find out how the area of the cross
section of the wire affects the resistance and also to find out the
resistivity of the wire having found the resistance over a certain
length and using a certain cross sectional area. I will also
experiment to see how the length of the wire affects the resistance.
Plan
The first thing that I will do is to set up the apparatus as shown
below.
A,V
Except for the experiment where I alter the length, I will keep the
length of the wire constant throughout the experiments and only change
the diameter of the wire. For each width I will record the p.d. and
current displayed on the voltmeter and ammeter. I will then use these
values to calculate the resistance of the wire at that length using
the formula:
[IMAGE]V = IR or R = V (where V = p.d., I = Current, and R =
Resistance)
I
I will then find the cross sectional area of the wire. To do this I
will find the diameter of the wire using a micrometer. Then I will
find the area of the cross section by using the formula:
Area = πr² (where A = Area of cross section, π = pi, and r = radius)
Once I have this value I will be able to calculate the resistivity of
the wire by substituting the values into this formula:
R=rl or r= RA (where A = Area of cross section, R = Resistance, l =
[IMAGE][IMAGE] A l length, and r= resistivity)
I will repeat this for all of the different diameters that I will test
but will remember to keep the length of the wire the same throughout.
The apparatus that I will use for this experiment are listed below:
· Power supply - This will be 3V of power and will be used to power
the circuit so that I can measure the resistance of the wire.
I also decided to use a wooden block to keep hold of the wire, because
A = cross sectional area of the connecting rod. l = length of the connecting rod.
To set up the experiment, a central force apparatus was calibrated and setup with a hanging
2) In the geometric figure the vertex V = 6 and the face, F = 6. Find the edge of the geometric figure using the formula.
This shows that there is a difference of 2cm between A and B, and B
these to sections is less than 3:1 ( with the longer side been the sling side) the
surface area of the potato chip, first I will put it in the beaker as
* Surface Area - This will not affect any of my results, as we are
Assumptions : In the Above Circuit current (I1 , I2 , I3 ) is assumed to be flowing in the conventional direction i.e Clockwise . The Source voltage denoted by XX has been assumed to be 86V.
If I am to use a square of side length 10cm, then I can calculate the
thickness 34 mm and length 30 cm at the same point on the ends of the
Surface area of cone (A) = lateral surface area of cone + area of base