In modern day mathematics, the use of decimals to determine accurate calculations is used in almost every situation. It is used so often that we forget that decimals haven’t always been around. They had to have come from somewhere, but where did they come from? The origination of the decimal system is often overlooked and undervalued, but the importance of decimals in modern mathematics is extremely significant. This is why Simon Stevin’s work on decimal arithmetic was such a huge impact on the advancement of mathematics.
Our world is filled with numbers, consequently, math plays an important role in our daily life. The development of the discipline math has been made great progress from the ancient times to now. It almost owes to the wisdom of the mathematicians. From the book, I comprehend many sources and processes of the generation of the mathematical theories and discoveries. On the one hand, there are many merits in this book.
Computers are one of the greatest inventions in the 20th century. With hundreds of electronic devices attached inside the computer and the flows of electrical energy, we can simplify our daily lives by only clicking on the mouse and typing on the keyboard. There are many types of computers nowadays. Huge and powerful computers are employed by governments and businesses to perform complex tasks and to store data. Computers are particularly good at performing repetitive tasks at speeds far faster than any human or team of humans can.
Example: 12% can be converted into a fraction as Rate per cent of a number: It is the product of equivalent fraction and the number. p% of A = Example: To find the value of 30% of 600. Solution: Required value = = 180. 30/100 is equivalent fraction of 30%. Relation among Rate per cent, Number and Value: Let us consider a number N. Example: If 20% of a number is 24, then what is the 65% of the number?
H=mc^T=(200g/1)(1cal/goc)(2oc/1)=400cal C=H/m^T=400cal/(20.1g)(2oc)=400cal/40.2 goc=9.95cal/ goc 3. H=mc^T=(200g/1)(1cal/goc)(2oc/1)=400cal C=H/m^T=400cal/(53.9g)(20c)=37.38cal/ goc 4. H=mc^T=(200g/1)(1cal/goc)(2oc/1)=400cal C=H/m^T=400cal/(65.3g)(20c)=3.06 cal/ goc 5. H=mc^T=(200g/1)(1cal/goc)(2oc/1)=400cal C=H/m^T=400cal/(70.5)(20c)=400cal/141goc=2.83 cal/ goc 6. H=mc^T=(200g/1)(1cal/goc)(2oc/1)=400cal C=H/m^T=400cal/(70.1g)( 20c)= 2.83 cal/ goc 7.
375,000 Cost of Vansanpathi = 150*120*(520/15) = Rs. 260,000 Cost of sugar = 200*120*(1200/100) = Rs. 120,000 Cost of preservatives and Packaging = Rs. 50,000 Casual labour charge = Rs. 15,000 Conversion rate paid by Pearson = 3 * 1000 * 50 = Rs.