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Practicles titrations
Solubility of calcium hydroxide
Solubility of calcium hydroxide
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Recommended: Practicles titrations
Finding the Solubility of Ca(OH)2
Aim:
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To determine the solubility of Ca(OH)2.
To carry out the aim of this experiment an experiment needs to be
planned and carried out. I am given the information that the
solubility of the Ca(OH)2 is between 1 to 1.5g per dm3. Also I am
given a standard solution of 1M hydrochloric acid (HCl) which may have
to be diluted to suit the measuring needs of the experiment.
Apparatus:
[IMAGE]
* 1g of Ca(OH)2.
* Pipette 25cm3
* 2 x 500cm3 beaker
* Conical flask 250cm3
* Burette
* White tile
* Burette stand
* Stand
* Indicator
* 300cm3 of Hydrochloric acid- standard solution (concentration of
0.05M)
* Distilled water
* Filter Paper
* Stirring rod
* Funnel
Method:
* Add 1g of Ca(OH)2 to 300cm3 of distilled water in a 500cm3 beaker.
Keep stirring the solution till the solid stops dissolving. This
leaves a saturated solution.
* Filter off the excess solid into another 500cm3 beaker using a
damp filter paper (distilled water).
* Repeat the filtration of the solution till there is no solid left.
Making sure to stir the solution in between the filtrations and
clean out the other beaker with plenty of water.
* This should leave 300cm3 of Ca(OH)2 saturated solution which will
be used in the titration experiment needed to find the
concentration of the solution.
* Use some of the Ca(OH)2 to rinse out the conical flask and the
pipette. Use some HCl to rinse out the burette.
The purpose for this lab was to use aluminum from a soda can to form a chemical compound known as hydrated potassium aluminum sulfate. In the lab aluminum waste were dissolved in KOH or potassium sulfide to form a complex alum. The solution was then filtered through gravity filtration to remove any solid material. 25 mLs of sulfuric acid was then added while gently boiling the solution resulting in crystals forming after cooling in an ice bath. The product was then collected and filter through vacuum filtration. Lastly, crystals were collected and weighed on a scale.
This paper describes the methods used in the identification, investigation of properties, and synthesis of an unknown compound. The compound was identified as calcium nitrate by a variety of tests. When the compound was received, it was already known to be one of twelve possible ionic compounds. The flame test identified the presence of the calcium anion in the compound. The compound tested positive for the nitrate cation using the iron sulfate test. At this point it was hypothesized that the compound was calcium nitrate. Reactivity tests and quantitative analysis comparing the unknown compound with calcium nitrate supported this hypothesis. Synthesis reactions were then carried out and analyzed.
We then took 1ml of the 10% glucose solution again using the glucose rinsed pipette and added it to test tube 1, we then filled the H2O rinsed pipette with 9ml of H2O and added it to test tube one; making 10ml of 1% solution.
Each subsequent trial will use one gram more. 2.Put baking soda into reaction vessel. 3.Measure 40 mL vinegar. 4.Completely fill 1000 mL graduated cylinder with water.
Put 1mL of 0.1M cobalt (II) chloride hexahydrate dissolved in 95% ethanol into a test tube. Then add 1mL of deionized water. Tap the end of the test tube to mix the solution and record the pertinent data in section 2 of the Data Table. Discard the solution in the appropriate container as directed to you by your lab instructor.
The mass of Mg + the mass of O2=mass of MgxOx. Knowing the mass of
Well, this looks like its using some calculations so what I would do is take my 0.045 M and equal it to the 0.25 mL of NH3 and multiply that by 45.0 mL and multiply it by 10 with an exponent of negative 3. Once all of that is multiplied together we should get an answer of 0.01135 moles of our HCI. Now we can find our “Concentration” Which means we would divide our moles (0.01125) to our vol in liters which is 0.025, once we do that, we get an answer of 0.045M of our NH3. Well, since we are on the topic of pH we know that we can use the formula: pH = -log (H3O+). Then what we would do is plug everything into the formula: pH equals -log (2.4 multiplied by 10 (with an exponent of -5). Once we find the answer to this and we add up all of our calculations, we can come to a conclusion that the answer is: 4.6197 as our pH.
The amount of hydrochloric acid. 3. The concentration of the hydrochloric acid. 4. The surface area of the calcium carbonate.
If there is not enough energy no reaction takes place. In a solution of 0.5M hydrochloric acid, there are less hydrochloric acid particles compared to that of 2M hydrochloric acid, therefore, there are less particles to react with magnesium particles thus meaning less chance of collisions between the two reactants: [IMAGE] Therefore, as the concentration of the hydrochloric acid is increased, the chances of collisions increase thus giving a faster rate of reaction. Apparatus: Beaker Hydrochloric acid Distilled water Measuring cylinder Pipette Test tubes Test tube rack Diagram: [IMAGE] Method: Measure out 10cm3 of hydrochloric acid, as the concentration requires, for each concentration its composition is: Moles Volume HCl Volume Water 2M 10 cm³ 0 cm³ 1.5M 7.5 cm³ 2.5 cm³ 1M 5 cm³ 5 cm³ 0.5M 2.5 cm³ 7.5 cm³ 0M 0 cm³
The Solubility of Potassium Nitrate Aim To investigate how the solubility of Potassium Nitrate is affected by Temperature. Background Knowledge Potassium Nitrate (KNO3) is an ionic compound. The strong ionic bonds hold the compound in an ionic lattice which gives KNO3 its crystalline structure. These ionic bonds also have other properties which will affect my investigation, I must be aware of these properties for greater accuracy in my method.
Solubility is defined as the maximum amount of a substance that will dissolve in a given amount of another substance at constant temperature and pressure. Solubility is typically expressed in terms of maximum volume or mass of the solute that dissolve in a given volume or mass of a solvent. Traditionally the equilibrium solubility at a given pH and temperature is determined by the shake flask method. According to this method the compound is added in surplus to a certain medium and shaken at a predetermined time. The saturation is confirmed by observation of the presence of un-dissolved material. Saturation can also be reached if the solvent and excess solute is heated and then allowed to cool to the given temperature. After filtration of the
of Copper Sulphate. To do this I plan to work out the amount of water
6. I then rinsed out the beaker and glass rod into the flask to make
Volume's Effect on a Copper Sulphate Solution We are trying to find out if the current though a copper sulphate solutions volume is increased. To find this information out I shall perform an experiment using the following equipment; · 1 power pack · 1 beaker · 2 carbon rods for anode and cathode · 1 ammeter · 1 measuring cylinder · 2 crocodile clip wirers I shall also be using 60cm3 volume of copper sulphate in my preliminary results to decide upon the concentration of copper sulphate and the voltage I shall use. The following diagrams show the step by step process in which I will do my experiment; [IMAGE] [IMAGE] [IMAGE] [IMAGE] I will take 10 readings from 10cm3 to 100cm3. I will repeat my experiment to give my experiment a fair average. I will keep the power pack the beaker the carbon rods the crocodile clips the ammeter the concentration of copper sulphate and the measuring cylinder the same each time I do the experiment this experiment.
the left so that the concentration of H is more than Me and so the