Beilstein Test Lab Report

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Purpose: To help students identify the functional groups in a mixture of two compounds by interpreting the IR spectroscopy, measuring the boiling point, comparing the physical and chemical properties of an unknown with a known substance. In addition, students will learn how impurities affect the boiling point and solubility of a substance. Procedure: The student will read the IR spectroscopy of the unknown first. Then perform various tests and measure the boiling point. Beilstein Test The Beilstein test determines if there is a haloalkane (R-Cl, R-Br, or R-I) in the mixture. A copper wire is heated to remove any residue. Then it is dipped into the sample and heated again to observe the presence of a green flame. The green flame confirms …show more content…

My mixture had an average boiling point of 99.5 degrees Celsius. My unknown C was positive for the Beilstein test, meaning that there is either a bromoalkane, chloroalkane or iodoalkane. The IR spectroscopy confirms this because there is a peak around 800 cm-1 which is the haloalkane range. It was slightly soluble; therefore, there might be a functional group that is polar such as an alcohol. Once again, the IR spectroscopy confirms this since the broad peak is located at around 3400 cm-1. Unknown C was negative for the Chromic acid test so there might be a tertiary alcohol or no alcohol. Since the IR has an alcohol I assume that there might be a tertiary alcohol. After completing the test, I can minimize the options that correspond to the IR and the tests to draw a conclusion for the functional groups found in the mixture. For my unknown C, I narrowed down the options to 2-methyl-2-butanol and 1-bromobutane because these compounds have a boiling point of 102 degrees Celsius which is close to my readings of 99 and 100 degrees Celsius. 2-Methyl-2-butanol has a tertiary alcohol, which prevents it from undergoing a chromic acid test and the 2-methyl-2-butanol has a bromoalkane which was identified by the Beilstein test and the

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