Identifying Five Unknown Chemicals I was given 5 unknown samples, which are sodium chloride, sodium thiosulfate, calcium carbonate, sodium bicarbonate and sodium nitrate and these samples are all white and solid. However, I don’t know which substance is which sample and I was only given some information about the physical and chemical properties of these substances. In order to identify the 5 unknown samples, knowing which sample is which substance, I have to carry out this experiment, finding out the chemical and physical properties of these samples. How can we identify five unknown chemical samples that seem to look the same? By doing this experiment, I can know the physical and chemical properties of these samples. After I get my results about the physical and chemical properties of these samples, I can compare my results with the information given by the past student and identify the 5 unknown samples, finding out which sample is which substance. Hypothesis ========== Hypothesis for this identify: After I finish this experiment, I suppose I can identify the 5 samples, knowing which sample matches which substance through finding the chemical and physical properties of the samples. Also, I will know what a chemical and physical property is and I will know how to find them out. Materials ========= Refer to, Chemistry Lab #1 – What’s the substance? I didn’t change most materials when I did this experiment, but I added 4 materials, which are: * 5 test tubes * 2 stoppers * 1 large piece of paper And I deleted 1 material, which is: * Spatula Methods ======= Refer to, Chemistry Lab #1 – What’s the substance? However, I changed some of procedures during my experiment, here is the changes I made in this experiment: * I only used the toothpick to place a small amount of each sample on a separate piece of paper, instead of the spatula.
At this point the identity of the unknown compound was hypothesized to be calcium nitrate. In order to test this hypothesis, both the unknown compound and known compound were reacted with five different compounds and the results of those reactions were compared. It was important to compare the known and unknown compounds quantitatively as well to ensure that they were indeed the same compound. This was accomplished by reacting them both with a third compound which would produce an insoluble salt that could be filte...
The technique used to narrow down the identity of unknown white compound were solubility test, pH test, flame test, and ion test. The first technique used to narrowed the properties of unknown white compound was using solubility test. To conduct solubility test, 0.25 gram of unknown white compound was dissolved in 100 mL of water. After carefully observing the change while string unknown white compound in water, the unknown white compound was soluble because it dissolved in water completely. Using bursen burner, matches and deionized water, flame test was conducted for unknown compound and it burned lilac color. Then compared the color of unknown white compound to other compound that were narrowed. The results of flame test for compounds that were narrowed down is shown in the following table. The pH test was conducted using litmus paper. 0.50 gram of unknown white compound was measured and dissolved in 10 mL of water in beaker. After dissolving, placed the litmus paper in solution and recorded the pH value of unknown compound which was neutral. Then compared the pH value of unknown white compound to compound that were narrow down. The pH result of the KCL, KNO3, NaCl, and K2SO4 is presented in the following table. The ion test was also conducted in order to make sure that the identity of unknown white compound was matched with the compound that were narrow down. After conducting the test, the result of unknown white compound which formed precipitate compared to KCl, KNO3,NaCl, and K2SO4. The results shown in the following
The procedure of the lab on day one was to get a ring stand and clamp, then put the substance in the test tube. Then put the test tube in the clamp and then get a Bunsen burner. After that put the Bunsen burner underneath the test tube to heat it. The procedure of the lab for day two was almost exactly the same, except the substances that were used were different. The
Experimental: The experimental procedure outlined in the OU Physical Chemistry Laboratory Manual was followed without any deviations.
Solid A was identified to be sodium chloride, solid B was identified to be sucrose, and Solid C was identified to be corn starch. Within the Information Chart – Mystery White Solid Lab there are results that distinguishes itself from the other 4 experimental results within each test. Such as: the high conductivity and high melting point of sodium chloride, and the iodine reaction of corn starch. Solid A is an ionic compound due to its high melting point and high electrical conductivity (7), within the Information Chart – Mystery White Solid Lab there is only one ionic compound which is sodium chloride, with the test results of Solid A, it can be concluded that is a sodium chloride. Solid B was identified as sucrose due to its low electrical
For this experiment, you will add the measured amount of the first sample to the measured amount of the second sample into its respectively labeled test tube then observe if a reaction occurs. In your Data Table, record the samples added to each test tube, describe the reaction observed, if any, and whether or not a chemical reaction took place.
Theophrastus Bomabastus Von Hoheneheim (Paracelsus) said “sola dosis facet venenum,” translated as, “all things are poisonous and nothing is without poison.” (Wink & Wyk, 2008) For people living in the Great Lakes regions of Northern Michigan, it often feels the opposite, “in everything there is medicine and nothing is without medicine.” Undoubtedly, some plants can externally or internally irritate the body affecting homeostasis, including instances of photo-sensitization and allergies; but generally these symptoms are not life threatening. According to herbalists and toxicologists, it is important to “distinguish between poisons that can kill in minute amounts, toxins that are less toxic than poisons, and toxicants that are toxic in high concentrations only.” (Wink & Wyk, 2008).
3.) Divide your 30g of white substance into the 4 test tubes evenly. You should put 7.5g into each test tube along with the water.
Nowadays, it will not be inept to inform that the universe is going over a construction boom. In truth, in the past few decades an entire affair of construction has altered dramatically like all other aspects of life. Currently, construction is no more just about keeping one brick above the other, but a diverse more than that. With the present scenario, the construction work encompasses all the aspects of construction like, performance, optimization, developing and designing. As an outcome, construction chemicals have become an essential part of the world construction industry. These chemicals are typically utilized to impart different properties into the layout.
Ever since the devastating results of the use of chemical weapons in World War One, the Organization for the Prohibition of Chemical Weapons (OPCW) has set up a convention to prohibit chemical weapons. 100 out of the 106 countries on our planet have signed this convention. One of the six countries that has yet to sign this convention is Syria. Syria has been the recent target of chemical weapon controversy, after a sarin gas attack in Damascus on its own citizens on the morning of August 21st, 2013. “1,429 innocent citizens including 426 children” were killed in this attack (BBC News). Syria’s stockpiling and transportation of chemical weapons has forced the hand of the United States executive branch. This forced foreign policy of the US is the “red line” that US can not back down from. The United States foreign policy with Syria is effective because Syria is following through with the destruction of its chemical weapons on the UN’s and United States’s timeline.
Since the third century A.D weapons that harness the power of chemical reactions have been used, intended for military use; however, in recent history terrorists have been able to acquire these gaseous weapons of mass destruction. After their release there is no possibility of containing chemical weapons as they are spread by the wind throughout a massive area. There are no moral implications for these weapons as they possess no positive use for society. Chemical weapons have plagued humanity since their creation with their unrestricted slaughter of soldiers and civilians, their use in mass genocides, and the damage caused to the environment.
The Uses and Significance of Group Two Compounds The group two elements consist of Beryllium, Magnesium, Calcium, Strontium, Barium and Radium. These are known as the ‘Group Two elements’ because of their unique electron division. Each one of these elements, consists of two outer shell electrons. Because of the lack of outer electrons, these elements are highly reactive. Group two electrons have a positive Two charge or +ve.
2- Using the available data to predict the physical and chemical properties of various chemical compounds.
Chemical Warfare is not the same as nuclear warfare, or the same as biological warfare. Chemical warfare involves using the deadly properties of chemical substances as weapons.Most weapons used in chemical warfare are considered to be“weapons of mass destruction” or, WMDs, and are not considered to be conventional weapons. Chemical warfare does not depend upon explosive force to neutralize targets; it depends on the chemical properties of a chemical agent weaponized. Defoliants are an example.They are used to kill off vegetation and deny its use of cover by the enemy. “Defoliants can also be used against agriculture and livestock to promote hunger and starvation but with protective equipment, and decontamination measures, the effects of defoliants can be neutralized. (fas.org)
The labels have fallen off of two bottles thought to contain solid sodium chloride or solid sodium carbonate. Describe a simple experiment which would allow you to determine which bottle contains which solid.