Titration Reaction Essay

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The chemical kinetics of the hydrolysis of t-butyl chloride was studied at different condition. The product concentration in this reaction can be determined by titration. The product concentration at different time intervals was recorded. The graph ln ([HCl]∞−[HCl]t) versus time was plotted in order to find the rate constant of the reaction. The rate constant was determined by obtaining the gradient of the graph. Aims: To determine the rate constant of a chemical reaction in different solvent mixtures. To observe and account for the change in reaction rates when different solvent system are used. Introduction: The hydrolysis reaction of a tertiary butyl chloride ((CH3)3C–Cl) is expected to proceed via an SN1 mechanism: (CH3)3C Cl (aq)  (CH3)3C + …show more content…

Since 1 mol of NaOH can react with 1 mol of HCl during titration, n(NaOH)=n(HCl) and [HCl]=n(HCl)/0.01L=0.0410M X (Volume of NaOH used in L) / 0.01L For instance, the concentration of HCl produced after first time interval in data table 1: [HCl]15’20’’ = (0.0021 X 0.041) mol / (0.01) L = 0.00861 mol L-1 Assume the alkyl halide was completely hydrolysed, [HCl]∞ = 0.1M. ln ([HCl]∞−[HCl]t) versus time from two data table: The rate of reaction was related to the change of concentration of t-butyl chloride and hydrochloride. The rate of change of reactant equal to the rate of change of product [(CH3)3CCl]t= [HCl]∞−[HCl]t  Equation 1 The rate of reaction was compared to find a linear rate versus t correlation. A constant was needed that was not related to the concentration, namely the rate constant k as shown as below: (-d〖[〖CH〗_3 CCl]〗_t)/dt=k〖[〖CH〗_3 CCl]〗_t  Equation 2 The equation 2 was rearranged and integrated on both sides from 0 to t, then Equation 1 was substituted into this new equation: 〖d[〖CH〗_3 CCl]〗_t/〖[〖CH〗_3 CCl]〗_t =-k dt  ln 〖[〖CH〗_3 CCl]〗_t/〖[〖CH〗_3 CCl]〗_0 =-kt  ln (〖[HCl]〗_∞-〖[HCl]〗_t)/〖[HCl]〗_∞ =-kt  ln[HCl]∞−[HCl]t = -kt +

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