Intermediate Inorganic Lab

336 Words1 Page

Intermediate Inorganic Lab Experiment 1: Preparation of Sodium Peroxoborate The experiment is designed to form the salt of a peroxy acid (sodium peroxoborate) from a salt (sodium borate) and hydrogen peroxide. The chemicals needed for the experiment are as following: 4.75 g. sodium borate, 1.0 g. NaOH, 5.75 mL of 30% sodium hydroxide, 12 mL of 0.1M HCl, 10 mL of 0.1N KMnO4, 0.2 g. KI, 5 mL of alcohol, and 5 mL of ether. The only required equipment is a 150 mL beaker, 125 mm test tubes, a Buchner funnel, filter flask, and an ice bath. Prepare sodium metaborate by dissolving 4.75 g. of borax (sodium borate) and 1.0 g. of sodium hydroxide in 20 mL of warm water. It may take a while for the sodium metaborate to dissolve, so in the meantime measure out 5.75 mL of hydrogen peroxide and chill in an ice bath. Once the NaBO2 has completely dissolved, put the flask in the ice bath. Dilute the chilled hydrogen peroxide with 15 mL of deionized water. Slowly add the diluted hydrogen peroxide dropwise while stirring. After all of the H2O2 is added, continue to stir for about 15 minutes. Filter the crystals by suction using a Buchner funnel and wash with 5 mL of alcohol, then 5 mL of ether. Weigh the product. Weigh out two 0.100 g. samples of the product and put each into a test tube. Add 6 mL of 0.1M HCl to the first test tube, then 0.1M KMnO4 and record results. To the second test tube also add 6 mL of 0.1M HCl. Make a solution of 0.165 g. of KI in 10 mL of water. Add the KI solution dropwise to the test tube and record results. I started with 4.750 g. of borax, and produced 9.119 g. in product. The product, NaBO3H2O, was a fine, white powder. My percent yield was 79.0%. In the section where you add HCl and KMnO4, the HCl dissolved the solid and when the KMnO4 was added, the test tube was covered

Open Document