Determining the Concentration of a Limewater Solution

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Determining the Concentration of a Limewater Solution Introduction Previous to conducting my experiment, research was carried out and the results of it adapted to aid me in solving the problem set. In the Advanced Chemistry Student’s Book by Nuffield, on page 86, I found a similar experiment to mine with a description of implementation, which aided me in the fact that I discovered the temperature of my solution did not need to be taken. This was because the solution of calcium hydroxide they used was saturated, and therefore they measured the temperature of the saturated solution along with its solubility, due to the fact that the solubility of saturated substances varies with temperature. This procedure will not be necessary in my particular experiment as the solution I will use will be far from saturated. Safety measures were observed and taken into account by looking at the hazard card for calcium hydroxide. I found the substance to have minimal hazards, especially when diluted in a non-saturated solution, and thus concluded the only precaution needed to be taken was to wear eye protection during handling of the solution. Lime water is a solution of calcium hydroxide (Ca (OH) 2) in water. Hydrochloric acid (HCl) reacts with calcium hydroxide to give calcium chloride (CaCl2). This reaction is given by the equation; 2HCl (aq) + Ca (OH) 2(aq) à CaCl2 (aq) + 2H2O (l) Prior to beginning the experiment I will choose an indicator to use when determining the exact point at which the limewater is neutralised. The colour change of an indicator is due to the change of one coloured form to another. Near the end point, both colou... ... middle of paper ... ...used using the equation: No. of moles (mol) = Concentration (mol dm-3) x Volume (dm3 Therefore 0.01 x 0.02425 = 0.0002425mol. To work out the number of moles of limewater used, the ratio of limewater to hydrochloric acid is 1:2, therefore 0.0002425/2 = 0.00012125. To work out the concentration of the limewater this figure is divided by the volume of limewater used using the equation: Concentration (mol dm-3) = No. of moles (mol) / Volume (dm3). Therefore 0.00012125/0.025 = 0.00485. To work out the concentration in g dm-3 we must first obtain the molar mass of calcium hydroxide which is 74.1. Using the equation: Mass (g) = Number of moles (mol) x Molar mass Therefore 0.00485 x 74.1 = 0.359385gdm-3. This being only accurate to approximately 0.36gdm3 due to the limited precision of the apparatus used.

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