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Concentration of sucrose
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Speeding Up the Dissolving Process 1.Planning Problem: What speeds up the dissolving process? Hypothesis: I think these factors will affect the dissolving process: vTemperature at which the reaction is carried out. v Particle size of the solute. v Stirring of the solution. However in my investigation, I am investigating temperature and the particle size of the solute. Prediction From using my scientific knowledge and understanding, if the particle size of the solute is smaller, the particles can easily diffuse with the solvent's particles and fill in the spaces between them. In addition, the surface area is also increased if the particle size of the solute is smaller, giving a greater area for the particles of the solvent to collide with, so the solute can dissolve quickly. If the temperature is high, more kinetic energy is given to the particles, therefore the particles would move faster, mix in with the particles of the solvent, and will easily dissolve in it. Variables inc. Different experiments with different strategies: Experiment 1: Investigating the rate of dissolving in various temperatures. Control Variable: 1. The solute is the same: sucrose;C12H22O6(sugar) 2. The solvent is the same: water; H2O 3. The mass of sugar is the same: 0.5 g 4. The size of the sugar particles is the same: granulated sugar. 5. The same quantity of water used: 25ml. 6. No stirring or movement for the particles. Independent Variable The temperatures are going to differ; this experiment is going to be split up for the various temperatures, therefore each boiling tube has water with different temperatures. In addition, a water bath is going to be used to get a high temperature. Dependent Variable Measuring the time, it takes to dissolve the sugar in the water, in minutes. Experiment 2: Investigating the rate of dissolving with different sizes of sugar particles: Control Variable: 1. The solute is the same: sucrose;C12H22O6(sugar) 2.
To begin the study, I first calculated how much of each solution I would need. I knew that the final volume of my reaction solution needed to me 30ml, so I calculated how much of starch, amylase, and tris buffer I would need. I used the formula Concentration (initial stock solution) x Volume (initial stock solution)= Concentration (final solution) x Volume (final solution). Using this formula, I found that I would need an initial concentration of 21 ml of starch, 1 ml of amylase, and 8 ml of the tris buffer. After calculating the amounts of substances I would need, I created two different solutions, one with the Carb Cutter and one without. Carb Cutter claims to block starch, however, to find this I needed to test the absorbance level of the control to compare the effect Carb Cutter had on the solution. Below is a graph showing the concentration of the control reaction over one minute intervals through the
CL-, as the ions of H+ and OH- react to form H2O. These spectator ions
Investigating the Effects of Varying Sugar Concentration on the Amount of Osmotic Activity Between the Solution and Potato Tubes
My Science fair topic is on Alka-Seltzer Tablets and its reaction time based on its particle sizes.
In a more concentrated solution, collision occurs more often because there are more molecules. The more often these molecules collide, the greater the chance they having of reacting. This means that the rate of a chemical reaction will increase if the concentration of reactants is increased. However, in this experiment, I'm going to do an investigation to find out how amylase concentration affects the rate of starch Hypothesis:
The Effect of Solute Concentration on the Rate of Osmosis Aim: To test and observe how the concentration gradient between a potato and water & sugar solution will affect the rate of osmosis. Introduction: Osmosis is defined as, diffusion, or net movement, of free water molecules from high to low concentration through a semi-permeable membrane. When a substance, such as sugar (which we will be using in the experiment we are about to analyse), dissolves in water, it attracts free water molecules to itself, and in doing so, stops them from moving freely. The effect of this, is that the concentration of (free) water molecules in that environment goes down. There are less free water molecules, and therefore less water molecules to pass across a semi-permeable membrane, through which sugar molecules and other molecules attached to them are too big to diffuse across with ease.
Variable Type Variable How to measure or control this variable Independent Potato We will put the cores of potato into sugar water and pure water and see how it affects it. Dependent Size of potato It is clearly visible too, but we will record the weight of the cores, before and after. Controlled The controlled variable is the water and the amount of sugar in it. We will measure and put the right amount of sugar concentration into each cup of water, 40% 30% 20% 10% and just pure water.
Table 2 shows the average percent change from the three trials. The average percentages were calculated by adding the percentages from the three trials for each cup and then dividing by three which was the number of trials. The calculations used to calculate water potential for each of the solutions are shown. The formula for solute potential used was -iCRT. Figure 1 shows the graph of the different sucrose solutions in relation to the water potential of those solutions.
Investigating the Solubility of Table Salt in Distilled Water at Different Temperatures The aim of this essay is to explain and discuss the drug cannabis and its effects in relation to biochemical, behavioural and psychological factors. The introduction will outline a brief history relating to the drug and include both the medicinal and recreational purposes of its use. The main discussion will explain how the drug chemistry affects the nervous system emphasising what neurotransmitter is effected and also what behavioural and psychological implications this has on the user.
... els of sucrose solution to distilled water (see molarity table above) and I placed each of the mixtures into the correct beakers. 5. Then I weighed all the potato chips on an electronic balance (see results) and recorded the results. 6. I placed 5 pieces of potato into each beaker and left them for approx 36 hrs. 7. After this time I drained out the solutions from the beakers and I carefully placed them in order of molarity on a paper towel. 8. I dried the potato chips gently and then weighed each potato piece and recorded the results. 9. As I had extra time I made a second experiment and also recorded those Results: Molarity (M) Starting Weight (g) (Results 1) Final Weight (g) (Results 1) Percentage Change (%) (Results 1) Start Weight (g) (Results 2) Final Weight (g) (Results 2) Percentage Change (%) (Results 2) These values clearly support my prediction, and even though there are some anomalous results, there is an overall negative trend across the whole set of results, proving them accurate. Analysis of Results: The sucrose concentration of the solution into which the potato tissue is placed affects to what degree it grows or shrinks. As you can see from the graph the results show a clear negative correlation, a very obvious inversely proportional trend. From this a conclusion can be drawn. When the water concentration is high, the potato gains water, as seen by the 0.0 molarity solution. When the water concentration is low, the potato loses weight and therefore decreases in mass, as seen in the 1.0 concentration solution. This proves my hypothesis correct. The results were quite widely ranged, as seen on the graph, wit ......
Our task was to investigate what the optimum ratio of solute to solvent that will produce the maximum cooling/heating effect?
Dissolution is the process of a solute dissolving in a solvent. There are three steps to the dissolution process. The first step is the solute particles to break apart. The second step is for the solute ions to enter the liquid. The third and last step is for the solvent molecules to surround the solute ions.
One major change I would make into the procedure is the to make a more efficient way to extract the sugar. To make it more efficient fi...
It was stated in the hypothesis that, “If cucumber slices are placed in water, ten percent sugar solution, and twenty percent water solution, then the cucumber in water will be isotonic (have the same measurement), the cucumber in the ten percent sugar water will become hypertonic (have smaller measurement), and the cucumber in the twenty percent sugar solution will be very hypertonic (even smaller). This is because of the process of osmosis and how things travel on the concentration gradient.” To test the hypothesis, three cucumbers were placed in three different solutions after being tested for their volume and mass. One solution held only water, another had 10% sugar, and the last had 20% sugar. After letting the cucumbers soak in each solution, their volume and mass was tested again. As shown in the table, the solution with only water had made the cucumber hypotonic. The volume was increased .16 and the mass increased .36g. In the 10% and 20% sugar solutions, the cucumber became hypertonic. The volume and mass of each cucumber had decreased. In the 10% solution, the volume went down by .16 and the mass went down .47g. In the 20% sugar solution, the volume decreased by .10 and the mass by .9g. The data collected from the lab proved our hypothesis was correct. One way to improve this lab would be to make sure the cucumbers were all the exact same size. This would make the data more accurate and easier to
I believe that the solubility of the KNO3 will increase at a proportional rate to the increase in the temperature of the water. [IMAGE]When the KNO3 dissolves, it can be classed as a chemical reaction. It follows therefore that in order for the KNO3 to dissolve, an activation energy barrier must be overcome. Activation energy is the energy required to kick-start a chemical reaction. If the activation energy barrier is not reached (i.e. if the particles do not have enough energy on collision to react) then the reaction will not proceed and the KNO3 cannot dissolve in the water.