Determining the Activation Energy of the Reaction Between Bromide Ion and Bromate Ion in Acid Solution

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Determining the Activation Energy of the Reaction Between Bromide Ion and Bromate Ion in Acid Solution

Objectives:

By reacting Potassium Bromide and Potassium Bromate in the acid

solution in varies temperature, we can then determine the Activation

Energy of the reaction in different temperature through the equation:[IMAGE].

Results:

Experiment Temperature

Time t/s

ln 1/t

Temperature K

1/K

80

≒0

N/A

353

2.83286119*10-3

50

21

-3.044522438

324

3.086419753*10-3

45

27

-3.295836866

316

3.164556962*10-3

40

42

-3.737669618

315

3.174603175*10-3

35

70

-4.248495242

311

3.215434084*10-3

30

113

-4.727387819

304

3.289473684*10-3

Questions:

1. Give an equation for the reaction between phenol and bromine.

[IMAGE]

2. What is the use of methyl orange in this experiment?

The methyl orange is used as an indicator for the reaction. Bromine

will be produces during the reaction and it will react with phenol

rapidly. Once all the phenol is used up, further bromine produced will

bleach the methyl orange immediately. So the rate of the reaction can

be calculated from the time for the indicator to be decolorized.

3. Based on your results, is it advisable to perform the experiment at

high temperatures such as 80℃?

From the above results, the time of the reaction is shorter as the

experiment temperature increase. So it is not advisable to perform the

experiment at high temperatures as the time of reaction is too short,

it is not easy for us to record.

4. Why is it not necessary to know how far the reaction has proceeded

at the point where the methyl red is decolourized?

In the experiment, the number of mole and the molarity of each

chemicals used are the same. And the appearance of the pink colour

only determines that there are some content of the reaction has

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