The Molarity of Sugar Solution Inside Potato Cells Background Information Osmosis Osmosis is the passage of water from a region of high water concentration through a semi-permeable membrane to a region of low water concentration. Semi- permeable membranes are very thin materials which only allow certain things to pass through them. They will allow small molecules like Oxygen, water and Carbon Dioxide to pass through. Water molecules can pass across the cell membrane in both directions
Purpose: The purpose of this experiment is to determine the molarity of a permanganate solution through the use of redox titration. Theory: The following are the reactions that take place in the experiment: Unbalanced: H2C2 O4 (aq) + MnO4- (aq)  CO2 (g) + Mn2+(aq) H2C2 O4 Half-Reaction: H2C2 O4 (aq)  2CO2 (g) + 2e- + 2H+(aq) MnO4- Half-Reaction: 8H+ + 2MnO4-(aq) + 5e-  Mn2+(aq) + 4H20 (l) Net Reaction: 5H2C2 O4 (aq) + 6H+ + 2MnO4- (aq)  10CO2 (g) + 2 Mn2+(aq) +8H20
The Effects of Sucrose Molarity on Cells in the Stem Tuber of a Potato Planning In this investigation I am trying to find out what molarity of sucrose solution is same as the molarity of sucrose in the cells of a potato. In this experiment I am going to change the molarity of the sucrose solution out the cells of potato. I predict that if the molarity of sucrose solution outside the cells is isotonic to the molarity of the sucrose inside the cells then there will be no change in weight
To have accurate data, it was best to test how the plant would be affected at a variety of different molarities. Molarity is the number of moles of solute dissolved in one liter of solution. Moles are the measure of the amount of material in a solution while molarity measures the concentration of material (Dulai, 2006). The different molarities shows how active the molecules in the solution of aspirin water is. One molar solution (1 M) is the molecular weight of the compound
experiment was to determine the effects of voltage and molarity changes on the fractal dimension of a Cu crystal formed by the re-dox reaction between Cu and CuSO4. Using the introductory information obtained from research, the fractal geometry of the Cu crystals was determined for each set of parameters. Through the analysis of data, it was determined that the fractal dimension is directly related to the voltage. The data also shows that the molarity is inversely related to the fractal dimension, but
CARBON DIOXIDE + WATER I can predict the reaction of my experiment to be: HYDROCHLORIC + CALCIUM à CALCIUM + WATER + CARBON ACID CARBONATE CHLORIDE DIOXIDE The Chemical Formula is listed below: 2HCl + CaCO3 CaCl2 + H20 + CO2 I think that as the molarity of the acid goes up, the amount of gas produced will also go up. I have based this on my knowledge that calcium carbonate does not react in water. Therefore in solutions with little acid and more water, the calcium carbonate will not react as much
Range of Sucrose Solutions Upon Potato Tissue Hypothesis ========== As the concentration of sucrose increases, the mass of potato decreases. Apparatus ========= 5 Test Tubes Sucrose solution of 0.0, 0.2, 0.5, 1.0, and 1.5 Molarity 10 piece of Potato Tissue Cork Borer Scalpel Beakers Weighing Scales Method ====== A standard sized cylinder of potato tissue is put into a beaker. Using a cork borer of a known size, in order to cut the cylinder of tissue
solution will decrease when it reaches 3:1 (salt: water). In put Variables: -Molarity -Size of potato -Mass of Water -Molarity of Sugar -Length of time in the solution -Temperature of water Out put variables: -Weight of potato Key variables: -Molarity of sugar. This is a key variable because it has the most effective outcome because osmosis only works when there are different molarities in and outside of the potato other wise the diffusion theory of osmosis wont work.
using our assigned volume. We know that: Molarity= # of moles/ # of liters, so: Trial 1. To find the number of moles we use the molarity formula: 30mL= 0.03L 0.2M = #of moles/ 0.03L = 0.006 moles of BaCl We know from the chemical formula that there is a 1/1 mole ratio between BaCl and BaSO, and that AW of 1 mol of BaSO = 233.404, so we transform moles to grams: 0.006 x (233.404g) =1.400g BaSO Trial 2. To find the no. of moles we used the molarity formula: 5.0 mL = 0.005L 0.2M = # of moles
water molecules pass though but not large ones. The flow continues until the concentration becomes the same on the inside as on the outside. This is called equilibrium. Molarity is a measure of concentration. Prediction I predict that the potato will change in mass and in length. I believe this because each Molarity of sucrose will change the potato's water content. This will happen because either the concentration will higher in the sucrose and lower in the Tubas or lower in the sucrose
of this experiment was to: create a dilute NaCl solution and calculate molarity, molality, and parts per million, experimentally determine the molarity of the same dilute NaCl solution through Mohr chloride precipitation technique, then, evaluate the accuracy by comparing the actual value to the experimental one. The actual molarity was calculated using the average density of three trials, mass of NaCl in solution, and molarity formula to be 0.0140 mol/L, the molality was calculated to be 0.0143,
acetic acid solution. This value was then divided by the volume of acetic acid solution originally added to the flask, 10.00 mL or 0.01 L, to obtain the molarity of the acetic acid solution; 0.8903 M. This process was replicated exactly a second and third time. The second titration required 31.39 mL of NaOH to be added, resulting in an acetic acid molarity of 0.8915 M. The third titration required 31.44 mL of
thought to be an acid or base is now classified as an acid or a base. For example Boron trifluoride is act as an acid an... ... middle of paper ... ...rstood titration is neutralization reaction. In acid-base titration solution without a known molarity is placed in an Erlenmeyer after it’s volume is measured. An indicator is added to the solution most of the time it is phenolphthalein. The solution with a known concentration is placed in burette with a tap in the end. By opening the tap slightly
the concentration of Acetic Acid by titrating with a known concentration of sodium hydroxide solution. The titrant is the solution with a known concentration that is titrated to the another solution with an unknown concentration to determine the molarity of the second solution. The analyte is a substance which is examined by analytical procedure; the properties of that solution are measured. In the first reaction the titrant was KHP and the analyte was NaOH, in the second one the titrant was NaOH
what caused the anomalous results, as it was lighter that the best fit line i.e. some water may have been lost through harder drying, or squeezing during the drying process. If some of the water evaporated overnight, it would have incresed the molarity of the solutions, thus making the results innaccurate. This could be combatted by putting a bung in the top of the test tubes to stop the evaporation and keeping the sugar slution concentrations the same. To improve the accuracy of the results
Introduction The purpose of this experiment was to test for quality control and analysis of a commercial product, in this case vinegar. The experiment performed determined the actual molarity of a specific brand of vinegar as compared to information provided on the bottle. The standardization of HCl and NaOH was also performed in order to understand the process of titrations. The importance of testing for quality control to be sure the product being sold holds up to its commercial value and is authentic
An Experiment to Investigate Osmosis in Plant Tissue Aim: To conduct an investigation to compare the osmotic behavior of two types of plant tissue in varying concentrations of sucrose solution. To find the point at which there is no change in mass or length of a specific plant tissue in a certain sucrose solution, the point of equilibrium, where sucrose and water contents are both equal in the solution and the tissue. Introduction: When a plant cell is placed in a sucrose solution there
Lab Day 3 6/2/17 Lab 9: Acids and Bases Purpose: The purpose of the lab is to calculate the concentration of a known acid. Using the data collected from this lab, you will calculate the molarity of the acid. Introduction: In chemistry, concentration is the amount of a substance in a given volume of space. Concentration is also the ratio of solute in a solution to either solvent or total
Solute Potential of Cell Sap of Plant Epidermal Cells Aim: To estimate the solute potential of a plant tissue. Results: Molarity of Solution Plasmolysed Cells Percentage of Cells That Were Plasmolysed .3M 1/70 .01% .4M 0/70 0% .5M 5/70 7% .6M 12/70 17% .7M 29/70 41% 1.0M 56/70 80% It must be taken into account, that the experiments procedure was changed. This could have had a great affect on the results. The part of the procedure
0M Glucose solution the molecular mass of glucose in grams is dissolved in 1dcm-3 of water. Below is the molecular mass of glucose. C 6 H 12 O 6 (6x12)+(1x12)+(6x16) 72+12+96=180g From 1.0M Glucose solution it is possible to make any desired molarities lower than 1.0M by mixing with the correct ratio of water. ------------------------------------------------------------------- Molority M cm3 of water cm3 of 1.0M Glucose 0.2 8