IV. PROPOSED CONVERTER WITH MAGNETIC COUPLING Power Circuit With Magnetic coupling Fig.4 SEPIC Converter With Magnetic Coupling The classical SEPIC and modified SEPIC without magnetic coupling is as shows fig. 3 and 4. Boost converter gain is half of the SEPIC converter without magnetic coupling but in some application extreme high gain is needed in such cases without magnetic coupling SEPIC converter compactable. One practical limitation of SEPIC converter is duty cycle should not be high because if duty cycle close to unity the static gain goes to infinity. To replaced L2 to mutual inductance which will acts as flyback transformer and its turns ratio increase the gain of the converter. But use mutual inductance developed reverse recovery …show more content…
Third Stage[t2-t3](Fig.9): At instant t2 The switch is turned off at the time t2. energy stored in L1 transfer to the Capacitor CM and also energy transfer through capacitor CS1 and CS2 4. Fourth Stage[t3-t4](Fig.10) : At time t3, CM finished energy get transfer at that instant the diode D1 is blocked. The energy transfer to output maintain till t4 till power switch is turn on. 5. Fifth Stage[t4-t5](Fig.11): When the Power switch is turn on at t4,the current is linearly decease of D0.which limits the reverse recovery current. when DO blocked the converter return to first stage. The static gain of the modified SEPIC converter with magnetic coupling and voltage multiplier is calculated by (4). where the inductor windings turns ratio (n) is calculated by Considering a duty cycle equal to 0.8, a static gain equal to q = 10 is obtained for n = 1, q = 15 for n = 2 and q = 20 for n = 3 and the switch voltage is equal to five times the input voltage for all cases. The static gain variation as a function of the duty cycle is presented in Fig. 10. V. SIMULATION RESULTS Using MATLAB /SIMULINK software model of single-ended primary inductance converter (SEPIC) with magnetic coupling modeled and simulated. The parameters for preferred converter with magnetic coupling are shown in
Electronic configuration: 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 4f14 5s2 5p6 5d9 6s1
It can be viewed from the Fig.6(a) that a constant 24V output has been obtained and also a continuous input current has also been obtained. Also, the output ripple current has been greatly reduced. Fig. 6(b) shows the input capacitor currents and the inductor current IL0, IL1 and IL2. Fig. 6(c) shows the voltage and current stress experienced by the switches and Fig. 6(d) shows the voltage and current stress experience by the diodes. The voltage stress experienced by the diodes and the switches is approximately equal to 110 V, i.e., the voltage stress present across the semiconductor devices is less than the input voltage whereas in the conventional interleaved buck converter, the voltage stress of the semi-conductor devices are equal to the input
The research involved in this paper has greatly enhanced our groups understanding of the technology involved in winding linear generators and will be a useful guide during the construction of our prototype.
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...gren X, Lijian T, Dangun Z, Yi X. “Calculation of end region magnetic field and circulating losses for turbo-generators using a coupled field and circuit equations method”, IEEE Trans Magn 1990;26:497–500.
Based on Kirchhoff’s current law it’s easy to obtain the current injection of node k as:
In design 4B, it is required to improve the problem for voltage and current of output stage cannot stop, and the ripple waveform. That is needs to finish the designed, improved and simulated the booster converter, final project presentation, the demonstration and the final project report writing work. Although it would be a great challenge because need to work in day time and can only spend the night time on the project.
6. Y. Hu,Y.Xie, H. Tian, and B. Mei, “Characteristics analysis of two channel interleaved boost converter with integrated coupling inductor,” in Proc.IEEE Power Electron. Spec. Conf., Jun. 2006, pp. 1–6.
Figure-1.1 depicts the traditional or conventional three-phase voltage-source converter (that can be abbreviated as V-source converter) structure. A dc voltage source which is supported by a large capacitor feeds the main converter circuit, a three-phase bridge. This dc voltage source can be a battery, fuel-cell stack, diode rectifier, or capacitor. Six switches have...
Storage of electrical energy is very important in many applications especially electrical appliances which require mobility or short burst of energy over a short duration of time. There had been many technologies developed to emulate characteristics of an ideal power supply which can store large amounts of energy, providing good power output as well as being able to be charged and discharged rapidly without deterioration of any type. A typical power storage device can be characterized by its power density and its energy density, noting that with our current technology, none which can achieve the best of both.
This section will discuss a comprehensive discussion regarding the modes of operation of the boost type converter, and the effect on overall converter performance as well.
Mode 2: Here the CSC converter is in off position, the inductor L1 discharges the stored energy to the DC link capacitor through diode D.
The area of Integrated Circuits and Systems fascinated me when I came across it the first time in my sophomore year of undergraduate academic curriculum. The theoretical courses and the lab work relevant to this area which I have undergone during these three years enhanced my interest and played a substantial role in moulding my skills. The never ceasing desire to know more beyond what the book tells me, and indulge in work apart from my prescribed regular course work motivated me take up various research internships and projects, workshops and technical competitions on the non-academic front. My first project, in my sophomore year at NIT Trichy, was a basic MATLAB/Simulink Design of Dynamic and Steady state analysis of Self Excited Induction Generator. This ...
...r fires every other revolution so the distributor shaft must revolve at one half crankshaft speed. After the high tension surge is produced in the ignition coil by the opening of the breaker points, the current passes from the coil to the center terminal of the distributor cap. From there, it passes down to the rotor mounted on the distributor shaft and revolves with it. The current passes along the rotor, and jumps the tiny gap to the cap electrode under which the rotor is positioned at that instant. This cap electrode is connected by high tension wiring to the spark plug. As the rotor continues to rotate, it distributes current to each of the cap terminals in turn. connected by high tension wiring to the spark plug. As the rotor continues to rotate, it distributes current to each of the cap terminals in turn.
In this section, The basics of electromagnetic transients, HV Capacitors banks and their relations and functions in the power system are presented.