Investigating the Reaction Between Bromine and Cyclohexane

1084 Words3 Pages

Investigating the Reaction Between Bromine and Cyclohexane

By adding bromine to a mixture of Cyclohexane and water, and placing

the mixture under a bright light and shaking from time to time,

Hydrogen Bromide is formed. This reaction is shown below:

[IMAGE]C6H12 + Br2 C6H11Br + HBr

When the bromine has all reacted and the red colour has gone, the

hydrogen bromide can be titrated with sodium hydroxide. This reaction

is shown below:

[IMAGE]HBr + NaOH NaBr + H2O

From this titration I can then work out the HBr formed per mole of

Bromine.

Results of my experiment

------------------------

Class results.

Group Number

Mass of Br2 (g)

Titre (cm3)

1

0.99

32.50

2

0.94

29.80

3

1.03

32.60

4

1.04

34.20

5

1.17

35.70

6

0.94

31.25

7

0.95

30.50

8

1.04

32.50

9

1.10

32.20

Average

1.02 to 2dp

32.36 to 2dp

Working out the mean averages

-----------------------------

To work out the mean averages I used the following formula:

Sum of column / number of groups

My results- with raw data

Original mass of stoppered flask (g)

Mass after Bromine was added

(g)

Mass of Br2

(g)

Initial burette volume

(cm3)

Final Burette volume

(cm3)

Amount of NaOH added

(cm3)

136.78

137.81

1.03

100

67.4

32.6

Using the results

-----------------

Bromine

I used a mass of 1.03grams of Bromine.

I arrived at this amount by weighing the volumetric flask without the

bromine added then I weigh the flask with the bromine added. The

different between which was 1.

Open Document