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How does concentration affect reaction rates
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The Enzyme Concentration and The Volume of Juice As the enzyme concentration increases so too does the volume of juice. This is because as the concentration of enzyme molecules increase there is more chance of a collision with an apple substrate molecule. If the chance of a collision is increased then the number of collisions will increase resulting in a higher rate of reaction. The enzyme combines with the substrate to form an enzyme-substrate complex. Enzyme + Substrate ¬¬¬> Enzyme-Substrate Complex The enzyme-substrate complex then breaks down to give the product and releases the enzyme in an unchanged form: Enzyme-Substrate Complex ¬¬¬> Product + Enzyme So I can conclude that the rate of reaction is directly proportional to the concentration of the enzyme. This is clear from the results that I myself obtained and from the class average. We can see that as the concentration of the enzyme increases so does the volume of juice (product) produced from the apple. This is because the more enzymes that are present the greater the number of active sites available for the substrate to fit into under the lock-and-key hypothesis, thus forming a greater number of enzyme-substrate complexes and thus forming a higher product rate (apple juice). Enzyme concentration is directly proportional to the rate of reaction provided the substrate concentration is maintained at a high level and the pH and temperature are kept constant. We know that the substrate concentration is maintained at the same level in all samples, this done by ensuring that all samples are of equal mass and we know that all the samples were placed in an incubator at 40°C thus ensuring that the temperature effects the rate of reaction in all samples in the same way. Graph: - From 0% ¬> 0.25% concentration we can see the greatest rate of reaction as there is an abundance of substrate molecules available to combine with the active site of the enzymes producing a large gradient on the graph. As concentration increases from 0.25% ¬> 0.
After conducting this experiment and collecting the data I would have to say that the optimal temperature for enzyme activity would have to be room temperature which in my experiment was thirty-four degrees Celsius. I came to this answer because the glucose test strip showed that at room temperature there was more glucose concentration that at either of the other temperatures. Due to temperature extremes in the boiling water the enzymes could no longer function because the breakdown of lactose stopped. The cold water also hindered the breakdown of the lactose but as the water warmed the enzymes were more active which can be seen in the results for the cold water at 20 minutes B. Describe the relationship between pH and the enzymatic activity of lactase.
This evidence alone suggests that higher increases in substrate concentration causes smaller and smaller increases in enzyme activity. As substrate concentration increases further, some substrate molecules may have to wait for an active site to become empty as they are already occupied with a substrate molecule. So, the rate of the reaction starts to level off resulting in a plateau in the graphs. This means that the reaction is already working at its maximum rate, and will continue working at that rate until all substrates are broken down. The only way the reaction rate would increase, is if more enzyme was added to the solution. This confirms that increases in substrate concentration above the optimum does not lead to greater enzyme activity. Therefore, the rate of reaction is in proportion to the substrate
For example, substrate concentration, enzyme concentration, and temperature could all be factors that affected the chemical reactions in our experiment. The concentration of substrate, in this case, would not have an affect on how the bovine liver catalase and the yeast would react. The reason why is because in both instances, the substrate (hydrogen peroxide) concentration was 1.5%. Therefore, the hydrogen peroxide would saturate the enzyme and produce the maximum rate of the chemical reaction. The other factor that could affect the rate of reaction is enzyme concentration. Evidently, higher concentrations of catalase in the bovine liver produced faster reactions, and the opposite occurs for lower concentrations of catalase. More enzymes in the catalase solution would collide with the hydrogen peroxide substrate. However, the yeast would react slower than the 400 U/mL solution, but faster than the 40 U/mL. Based on this evidence, I would conclude that the yeast has a higher enzyme concentration than 40 U/mL, but lower than 400
Catalase is a common enzyme that is produced in all living organisms. All living organisms are made up of cells and within the cells, enzymes function to increase the rate of chemical reactions. Enzymes function to create the same reactions using a lower amount of energy. The reactions of catalase play an important role to life, for example, it breaks down hydrogen peroxide into oxygen and water. Our group developed an experiment to test the rate of reaction of catalase in whole carrots and pinto beans with various concentrations of hydrogen peroxide. Almost all enzymes are proteins and proteins are made up of amino acids. The areas within an enzyme speed up the chemical reactions which are known as the active sites, and are also where the
Enzymes are proteins that increase the speed of reactions in cells. They are catalysts in these reactions which means that they increase the speed of the reaction without being consumed or changed during the reactions. Cofactors are required by some enzymes to be able to carry out their reactions by obtaining the correct shape to bind to the other molecules of the reaction. Chelating agents are compounds that can disrupt enzyme reactions by binding to metallic ions and change the shape of an enzyme. Catechol is an organic molecule present under the surface of plants. When plants are injured, catechol is exposed to oxygen and benzoquinone is released because of the oxidation of catechol. Catecholase aids in the reaction to produce
In this investigation, the concentration of enzyme will be inversely proportional to the time taken for starch to be digested, until at a certain point where it will level out. It will level out because, all the substrates would have been used up, therefore there will be no more substrates for the enzymes to work on. In effect, the concentration of the substrate will act as a limiting factor. However, enzyme concentration will be directly proportional to the rate of reaction.
Investigating the Effect of Substrate Concentration on Catalase Reaction. Planning -Aim : The aim of the experiment is to examine how the concentration of the substrate (Hydrogen Peroxide, H2O2) affects the rate of reaction. the enzyme (catalase).
The three-dimensional contour limits the number of substrates that can possibly react to only those substrates that can specifically fit the enzyme surface. Enzymes have an active site, which is the specific indent caused by the amino acid on the surface that fold inwards. The active site only allows a substrate of the exact unique shape to fit; this is where the substance combines to form an enzyme- substrate complex. Forming an enzyme-substrate complex makes it possible for substrate molecules to combine to form a product. In this experiment, the product is maltose.
As Enzyme concentration increases, enzyme activity will increase, because there are more enzymes to catalyze reactions.
Input variables In this experiment there are two main factors that can affect the rate of the reaction. These key factors can change the rate of the reaction by either increasing it or decreasing it. These were considered and controlled so that they did not disrupt the success of the experiment. Temperature-
The higher the concentration of pectinase enzyme, the greater the yield of apple juice there will be.
On a two pieces of paper, we drew a cross and place a beaker on top of
Abstract: Enzymes are catalysts therefore we can state that they work to start a reaction or speed it up. The chemical transformed due to the enzyme (catalase) is known as the substrate. In this lab the chemical used was hydrogen peroxide because it can be broken down by catalase. The substrate in this lab would be hydrogen peroxide and the enzymes used will be catalase which is found in both potatoes and liver. This substrate will fill the active sites on the enzyme and the reaction will vary based on the concentration of both and the different factors in the experiment. Students placed either liver or potatoes in test tubes with the substrate and observed them at different temperatures as well as with different concentrations of the substrate. Upon reviewing observations, it can be concluded that liver contains the greater amount of catalase as its rates of reaction were greater than that of the potato.
The claim stated that the reaction rate of an enzyme will decrease when the pH is changed. The data(see Table 1) supports this hypothesis. The reaction rate of the enzyme decreased when the pH was affected. After 180 seconds of testing, the number of Pop Beads metabolized dropped from 31 in normal conditions to 8 when affected by a change in pH. Secondly, in the yeast lab, the data taken displays the effects of temperature, pH, and concentration on the reaction rate of catalase. The claim stated that changing these variables will result in a decreased rate of reaction. The data refutes this claim. Over the course of five trials, the reaction rate of catalase did not decrease after manipulating variables of temperature, pH, and concentration(see Table 2). This is evident because the time it took for the paper to rise did not decrease at all when variables were
In this experiment, researchers used different measurements of catechol and 1cm of potato extract. Researchers hypothesized that the increase in substrate would level out the enzyme activity by