Cabbage Patch Lab In this week’s lab, I had to determine the pH of several liquids. My question was “How acidic or basic are each of the liquids?”. Indicators are compounds that change color at a specific pH level when added to a substance. The indicators I used in this lab were cabbage juice and litmus paper. Now that I have a question and background information, I can move on to form a hypothesis. I had 5 different hypotheses for each of the liquids. If I dip the litmus paper in the distilled water, then it will be neutral. If I dip the litmus paper in the vinegar, then it will be an acid. If I dip the litmus paper in the apple cider vinegar, then it will be an acid. If I dip the litmus paper in the laundry detergent then it will be a base. And finally, if I dip the litmus paper in lime juice, then it will be a base. There is an independent and dependent variable, a control group, and a constant in every lab. The independent variable in this lab is the color of the liquids. The dependent variable is the the pH. The control group is the cabbage juice, …show more content…
The materials I used in this lab were red cabbage juice, red and blue litmus paper, measuring cups, a paper towel, distilled water, vinegar, apple cider vinegar, laundry detergent, lime juice, a pH chart, and finally, a dropper. The first step in this lab report is to take one drop of cabbage juice from the measuring cup and put it into the other measuring cups, or the other 5 liquids, and mix the solution together. Next, using the pH chart, decide the color of the solution and record the results. Third, dip the red and blue litmus paper into all of the measuring cups and place them on a paper towel to determine whether each substance is an acid or base using the pH scale. And finally, record all your results in the data chart putting the number each solution is under “pH”, and putting acidic, basic, or neutral under “effect on litmus
Data table 1 Well plate Contents Glucose concentration A 3 drops 5% sucrose + 3 drops distilled water Negative B 3 drops milk+3 drops distilled water Negative C 3 drops 5% sucrose +3 drops lactase Negative D 3 drops milk +3 drops lactase 15+ E 3 drops 20% glucose +3 drops distilled water 110 ++ Questions B. In this exercise, five reactions were performed. Of those reactions, two were negative controls and one was a positive control.
...ost likely to be battery acid. If it is water, it has a Ph level of around 7. For vinegar, the Ph level is approximately 2.4 - 3.4. Thus, once testing the liquid compare it with the Ph levels above to discover the mystery solution.
What are the effects of different solutions on the size of a cell? To find a solution this problem my group conducted an experiment/lab. The variables changed (Independent Variable) were the solutions, and the results were the change in size of the gummy bear/cell (Dependant Variable). The control group,to compare our results, was a gummy bear that was not put into any solution. The standardized variables were the color of the gummy bear, the same brand of cup, the amount of solution in each cup, and the amount of time each gummy bear spent in the solution.
Apparatus: * 1 measuring cylinder * 1 test tube * 1 stop clock * A large gelatine cube containing indicator and NaOH * Hydrochloric acid ranging from 1-3 molars * A scalpel Diagram: Method: * Take the large gelatine cube and cut into 15 equal pieces * Place on piece of the cube into the test tube * Measure out 10mls of HCl in the measuring cylinder * Pour the HCl into the test tube with the gelatine cube and start the clock * Time how long it takes for the pink colour inside the gelatine cube to completely disappear * You will also notice that the cube dissolves slightly * Record your results and repeat this same process 3 times for each molar of acid: § 1 molar § 1.5 molar § 2 molar
The hypothesis to this experiment is "if you place a plant under water in direct sunlight, then it will produce oxygen bubbles." In this experiment the independent variable where the plant is placed. The dependent variable is the water the plant is put in. Your controlled variable would both be the type of water used and the type of plant used. The conclusion to this experiment would still ben your hypothesis because its true which is " if you place a plant under water in direct sunlight, then it will produce oxygen bubbles." The only flaws in this experiment were that they used the same type of water and they did not try any other water. I believe that this experiment is
The test is to see if spinach leaves discs can be effected by photosynthesis. I predicted that more disc would float in the light than in the dark. After writing down my hypothesis, I put the discs in water on a petri dish and waited 15 minutes. I then recorded if the in the light were floating or not. I also found out that the disc will also change color when they are in the light or in the dark. The hypothesis is supported when the light does have more disc floating in the petri dish than the dark did. I also determined other things as well such as the the dependent and independent variables, and the control treatments. The independent variable is the amount of oxygen in the discs. The dependent variable is the light, darkness, and the amount
The purpose of the experiment was to examine the amount of acid neutralized by using an unknown sample of antacid.
acid. This will let me take at least five sets of results, and if the
The experiment, focuses on the effects of acidic drinks on teeth. In this experiment, the scientist is trying to answer which liquids; Arnold Palmer, Coffee, Coca Cola, V8 Splash Tropical Blend, and crest pro-health toothpaste, affect your tooth enamel the most. The Independent Variable are four ounces of each liquid, and the dependent variable is the staining of teeth. The Constants are the toothpaste, toothbrush, the amount of time the eggs stay in the liquid, and the type of eggs used. The units used while measuring the effect of liquids on teeth is ounces.
For this experiment, you will add the measured amount of the first sample to the measured amount of the second sample into its respectively labeled test tube then observe if a reaction occurs. In your Data Table, record the samples added to each test tube, describe the reaction observed, if any, and whether or not a chemical reaction took place.
It changes from blue to red with acids but loses its colour in the presence of certain chemicals, one of which is vitamin C. DCPIP solution can be used to test for the presence of vitamin C in foods. Hypothesis Orange juice has the highest content of vitamin C. Citrus fruits have a higher content of vitamin C. The orange and lemon juice contain more vitamin C than the pineapple juice. Furthermore, as lemons are more acidic than oranges, I predict that the orange juice will contain more vitamin C than the lemon juice. Vitamin C affects, the ph the more vitamin C the higher the ph. Variables Independent Variables Different fruit juices (Pineapple, orange and lemon).
Independent variables: The temperature of hcl gas will be decreased and increased throughout the experiment.
The design for this study will be a simple between subject experiment consisting of one experimental group and one control group. The independent variable will be warm colors. The dependent variable will be mood. The main goal is to determine if the independent variable will influence or cause difference in the specified dependent variable. The experiment group will spend 60 minutes in a warm paint color room and their mood will be measured. The control group will spend 60 minutes in a neutral paint color room and their mood will be measured.
Based on the experiment using the red cabbage, I can tell if a liquid is an acid, base or neutral using red cabbage juice as an indicator.
For the solid sodium chloride, using distilled water will make it an aqueous solution. Just like before using red and blue litmus paper will only indicate that the sodium chloride is neutral. The same can be done for sodium carbonate since it is soluble in distilled water, making it easy to determine whether it is an acid or base when using litmus paper. In this case, sodium carbonate is a base so red litmus paper will turn blue when the solution of sodium carbonate is dripped on to it.