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    going to investigate the rate of diffusion of Hydrochloric Acid into Gelatine. To do this I will use the same concentration and amount acid with the gelatine being cut into different sizes. The rate of diffusion is dependant on the surface/volume ratio to how quick the acid is able to diffuse throughout the whole of the gelatine. Equipment ========= § Hydrochloric Acid § Gelatine § Tile § Test tube § Rubber Bung § Scalpel § Ruler § Stop Clock § Goggles §

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    Heat Loss Investigation

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    Heat Loss Investigation Aim To investigate how variations in surface area and volume ratios in organisms lead to variations in heat loss and retention. Introduction Large animals have the ability to retain heat more easily than smaller animals because they have a larger surface area to volume ratio. This is the what I am trying to prove in the experiment. There are examples of this in nature. In winter the robin fluffs its wings up in order to retain more heat. When it does this

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    The Physics of Turbo Chargers

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    it easy to compress a gas. Which gives low mass to volume ratio. Particles must be in continual motion. These particles are very fast (usually about 500 meters per second). The molecules in a gaseous state have enough kinetic energy to be essentially independent of each other. Pressure is a main factor in turbo chargers. Pressure is the force exerted on a surface divided by the area of the surface (force per unit area). Decreasing the volume increases the pressure. The average speed of the molecules

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    Cells And Cell Theory

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    surface-to-volume ratio than larger cells and therefore can "feed" all areas of the cell in less time. What is "surface-to-volume ratio," and how does it affect cell size? The surface-to-volume ratio is a mathematical relationship between the volume of an object and the amount of surface area it has. This ratio often plays an important role in biological structures. Think of a cell as a sphere: The surface area of a sphere can be calculated by 4ð r2 where r is the radius of the sphere. Volume of a sphere

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    [IMAGE] AMOEBA Amoeba [IMAGE] ELEPHANT Elephant Since an amoeba is small it has a large surface area compared to its volume. Since an elephant is large its surface area is small in comparison with its volume. As can be seen below if one increases the surface area of an object, the total volume increases but the surface area: volume ratio decreases. 3cm [IMAGE] 2cm [IMAGE] 1cm [IMAGE] Total SA= 6 24 54

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    How does surface area to volume ratio affect the rate of diffusion? As the gelatin cube sizes were cut into smaller pieces, the surface area to volume ratio increases. Surface area to volume ration is very important in living organisms, since all the nutrients and oxygen need to diffuse through the cell membrane into the cells. The surface area to volume ratio affects the rate in which the salt diffused through the solution by how the salt diffused out of the gelatin and into the water this relates

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    The uropod at the rear of the Woodlouse is used for the uptake of water and this is achieved when they are pressed against moist surfaces5. Woodlice cannot retain water for long periods of time and because they have a large surface area to volume ratio they loose water quickly by diffusion6. Their exoskeleton is not waterproof which means that they will also loose water through this. Fig 1. Dorsal View of Porcellio scaber [IMAGE] The ventral view of the anatomy of Woodlice (fig

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    cools down in cups with different materials. Prediction: The factors which will affect the amount of heat loss are: § Material of the cup – Conduction § Colour – Radiation § Surface area of cup § Amount of water (surface area:volume ratio) § If the cup has a lid or not – Convection and Evaporation § Room temperature § Thickness of the cup § Temperature of the liquid § Air movements – Convection/Evaporation I will be investigating the material of the cup. I experimented

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    Demonstrating How Surface Area and Volume Affect Heat Loss in Animals Planning ======== Aim: To investigate how surface area and volume of an animal affects the amount of heat lost. Planning a simple procedure =========================== One standard test tube, one boiling test tube, and one centrifuge test tube will be filled with water at 40°C. A thermometer will be placed in each tube to measure the decrease in temperature of the water. This will be timed for 300 seconds

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    will then have a set of results. Equipment [IMAGE] Prediction I predict that the big can with the larger surface area will keep the water the warmest. I think this because large animals' surface area to volume ratio causes very little heat loss where as small animals ratio is better for heat loss. It is also known that larger things such as animals cool down slower. Therefore this shows why I predict that the large can will keep the water the warmest.

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