Free Molarity Essays and Papers

The Molarity of Sugar Solution Inside Potato Cells Background Information Osmosis Osmosis is the passage of water from a region of high water concentration through a semi-permeable membrane to a region of low water concentration. Semi- permeable membranes are very thin materials which only allow certain things to pass through them. They will allow small molecules like Oxygen, water and Carbon Dioxide to pass through. Water molecules can pass across the cell membrane in both directions

Purpose: The purpose of this experiment is to determine the molarity of a permanganate solution through the use of redox titration. Theory: The following are the reactions that take place in the experiment: Unbalanced: H2C2 O4 (aq) + MnO4- (aq)  CO2 (g) + Mn2+(aq) H2C2 O4 Half-Reaction: H2C2 O4 (aq)  2CO2 (g) + 2e- + 2H+(aq) MnO4- Half-Reaction: 8H+ + 2MnO4-(aq) + 5e-  Mn2+(aq) + 4H20 (l) Net Reaction: 5H2C2 O4 (aq) + 6H+ + 2MnO4- (aq)  10CO2 (g) + 2 Mn2+(aq) +8H20

The Effects of Sucrose Molarity on Cells in the Stem Tuber of a Potato Planning In this investigation I am trying to find out what molarity of sucrose solution is same as the molarity of sucrose in the cells of a potato. In this experiment I am going to change the molarity of the sucrose solution out the cells of potato. I predict that if the molarity of sucrose solution outside the cells is isotonic to the molarity of the sucrose inside the cells then there will be no change in weight

the Pervis vinegar sample, four tests were needed. A molarity test was completed, a sample of the vinegar was then allowed to grow on an agar plate to ascertain whether bacteria were present and a pH test would also be done. The final test was a precipitant test to discover if the heavy metal Lead was present in the Pervis sample. A titration experiment was now set up using Sodium Hydroxide solution as the alkali in the burette with a molarity 0.01177 and 25ML of Pervis vinegar was placed in the

experiment was to determine the effects of voltage and molarity changes on the fractal dimension of a Cu crystal formed by the re-dox reaction between Cu and CuSO4. Using the introductory information obtained from research, the fractal geometry of the Cu crystals was determined for each set of parameters. Through the analysis of data, it was determined that the fractal dimension is directly related to the voltage. The data also shows that the molarity is inversely related to the fractal dimension, but

Range of Sucrose Solutions Upon Potato Tissue Hypothesis ========== As the concentration of sucrose increases, the mass of potato decreases. Apparatus ========= 5 Test Tubes Sucrose solution of 0.0, 0.2, 0.5, 1.0, and 1.5 Molarity 10 piece of Potato Tissue Cork Borer Scalpel Beakers Weighing Scales Method ====== A standard sized cylinder of potato tissue is put into a beaker. Using a cork borer of a known size, in order to cut the cylinder of tissue

CARBON DIOXIDE + WATER I can predict the reaction of my experiment to be: HYDROCHLORIC + CALCIUM à CALCIUM + WATER + CARBON ACID CARBONATE CHLORIDE DIOXIDE The Chemical Formula is listed below: 2HCl + CaCO3 CaCl2 + H20 + CO2 I think that as the molarity of the acid goes up, the amount of gas produced will also go up. I have based this on my knowledge that calcium carbonate does not react in water. Therefore in solutions with little acid and more water, the calcium carbonate will not react as much

Lima bean and wheat seeds will be used and it takes about five days to germinate. The independent variable will be the molarity of aspirin water from 0.2, 0.4, 0.6, 0.8 and 1.0 M. Molarity is used to express concentrations of plant hormones. The height of the lima bean and wheat seed plant when finished growing is the dependent variable. The growth will be measured using a ruler in centimeters to see which

solution will decrease when it reaches 3:1 (salt: water). In put Variables: -Molarity -Size of potato -Mass of Water -Molarity of Sugar -Length of time in the solution -Temperature of water Out put variables: -Weight of potato Key variables: -Molarity of sugar. This is a key variable because it has the most effective outcome because osmosis only works when there are different molarities in and outside of the potato other wise the diffusion theory of osmosis wont work.

using our assigned volume. We know that: Molarity= # of moles/ # of liters, so: Trial 1. To find the number of moles we use the molarity formula: 30mL= 0.03L 0.2M = #of moles/ 0.03L = 0.006 moles of BaCl We know from the chemical formula that there is a 1/1 mole ratio between BaCl and BaSO, and that AW of 1 mol of BaSO = 233.404, so we transform moles to grams: 0.006 x (233.404g) =1.400g BaSO Trial 2. To find the no. of moles we used the molarity formula: 5.0 mL = 0.005L 0.2M = # of moles

water molecules pass though but not large ones. The flow continues until the concentration becomes the same on the inside as on the outside. This is called equilibrium. Molarity is a measure of concentration. Prediction I predict that the potato will change in mass and in length. I believe this because each Molarity of sucrose will change the potato's water content. This will happen because either the concentration will higher in the sucrose and lower in the Tubas or lower in the sucrose

Variables: The variables for this practical are: 1. The metal that it used- magnesium, copper or iron. 2. The amount of metal that is used- any amount as long as it is divisible by 0.5 grams. 3. The concentration of the solution of the solution- molarity 0.1M or 0.5M. I am going to change the amount of metal. Fair Test: To make this a fair test I must keep everything constant except the variable (the amount of metal). But even the variable must be changed at a consistent rate (going up in

of this experiment was to: create a dilute NaCl solution and calculate molarity, molality, and parts per million, experimentally determine the molarity of the same dilute NaCl solution through Mohr chloride precipitation technique, then, evaluate the accuracy by comparing the actual value to the experimental one. The actual molarity was calculated using the average density of three trials, mass of NaCl in solution, and molarity formula to be 0.0140 mol/L, the molality was calculated to be 0.0143,

Assigned molarity of the first sample of Mandelic acid is .02, and assigned molarity of the second sample of Mandelic acid is .2. Assigned molarity for the first sample of acetic acid is .2, and the assigned molarity of the second sample of acetic acid is .4 Systematic errors are a malfunction of pH measuring probes. Possible malfunction in the scale concerning

acetic acid solution. This value was then divided by the volume of acetic acid solution originally added to the flask, 10.00 mL or 0.01 L, to obtain the molarity of the acetic acid solution; 0.8903 M. This process was replicated exactly a second and third time. The second titration required 31.39 mL of NaOH to be added, resulting in an acetic acid molarity of 0.8915 M. The third titration required 31.44 mL of

the concentration of Acetic Acid by titrating with a known concentration of sodium hydroxide solution. The titrant is the solution with a known concentration that is titrated to the another solution with an unknown concentration to determine the molarity of the second solution. The analyte is a substance which is examined by analytical procedure; the properties of that solution are measured. In the first reaction the titrant was KHP and the analyte was NaOH, in the second one the titrant was NaOH

what caused the anomalous results, as it was lighter that the best fit line i.e. some water may have been lost through harder drying, or squeezing during the drying process. If some of the water evaporated overnight, it would have incresed the molarity of the solutions, thus making the results innaccurate. This could be combatted by putting a bung in the top of the test tubes to stop the evaporation and keeping the sugar slution concentrations the same. To improve the accuracy of the results

0M Glucose solution the molecular mass of glucose in grams is dissolved in 1dcm-3 of water. Below is the molecular mass of glucose. C 6 H 12 O 6 (6x12)+(1x12)+(6x16) 72+12+96=180g From 1.0M Glucose solution it is possible to make any desired molarities lower than 1.0M by mixing with the correct ratio of water. ------------------------------------------------------------------- Molority M cm3 of water cm3 of 1.0M Glucose 0.2 8

thought to be an acid or base is now classified as an acid or a base. For example Boron trifluoride is act as an acid an... ... middle of paper ... ...rstood titration is neutralization reaction. In acid-base titration solution without a known molarity is placed in an Erlenmeyer after it’s volume is measured. An indicator is added to the solution most of the time it is phenolphthalein. The solution with a known concentration is placed in burette with a tap in the end. By opening the tap slightly

Solute Potential of Cell Sap of Plant Epidermal Cells Aim: To estimate the solute potential of a plant tissue. Results: Molarity of Solution Plasmolysed Cells Percentage of Cells That Were Plasmolysed .3M 1/70 .01% .4M 0/70 0% .5M 5/70 7% .6M 12/70 17% .7M 29/70 41% 1.0M 56/70 80% It must be taken into account, that the experiments procedure was changed. This could have had a great affect on the results. The part of the procedure