PURPOSE The purpose of this experiment is to use our knowledge from previous experiments to determine the exact concentration of a 0.1M sodium hydroxide solution by titration (Lab Guide pg.141). QUESTION The question that was proposed for investigation was: Can the exact concentration of 0.1M sodium hydroxide solution be determined by titration (Lab Guide pg. 141)? BACKGROUND DISCUSSION For this experiment we used titration to standardize the exact concentration of NaOH. Titration is the process
The Determination of the Solubility of Calcium Hydroxide I have to plan an experiment to find the solubility of calcium hydroxide, Ca(OH)2, in water. I have to make up a solution of calcium hydroxide and carry out a titration using hydrochloric acid solution of the chosen concentration. The equipment need is as below: · Solid calcium hydroxide · Methyl orange indicator · Volumetric flask (250cm3) · Clamp and boss · Clamp stand · Burette (50cm3) · Conical flask ·
standardized solution of sodium hydroxide solution (NaOH) and to determine the concentration of given unknown sulfuric acid (H2SO4) solution. Analysis: This experiment is divided into two parts. In the first part; the standardized solution of sodium hydroxide is prepared by titrating it with base Potassium hydrogen phthalate (KHP). Phenolphthalein (range 8.3 to 10.0) is used as indicator to determine whether the titration is completed. Part A: Standardization of a sodium hydroxide solution NaOH Code sample
Investigating a Neutralisation Reaction Between Hydrochloric Acid and Sodium Hydroxide To investigate a neutralisation reaction I must know all the factors that affect it in order to investigate in this. Here are all the factors; Temperature - This will defiantly affect an exothermic or endothermic reaction. Concentration - If the solution is made more concentrated it means it contains more particles of reactant, therefore more collisions are likely and an result of this is that the
Investigation into the solubility of Calcium Hydroxide Ca(OH)2 Planning ======== Calcium Hydroxide is a strong base which is alkaline in water. Lime water containing approximately 0.015 mol dm-3 will be used for the titration. HCl will be used also, and has a concentration of 0.3 mol dm-3 . Aim: The aim of the investigation is to determine the solubility of Calcium Hydroxide by calculating the concentration by means of a titration. Plan: Clamp stand Burette [IMAGE][IMAGE][IMAGE]Titration
Finding the Concentration of Calcium Hydroxide by Titration with Hydrochloric Acid. The Problem Perform a titration upon Calcium Hydroxide to find the concentration by using Hydrochloric Acid of 3 different concentrations as following 2 molar, 0.5 molar and 0.1 molar. In order to calculate the results must be within 0.05cm3 of each other. Apparatus Burette Volumetric Pipette Beakers Conical Flasks Volumetric Flasks Funnel Clamp Stand White Tile Fair Test
Energy In this lab, we dissolved Sodium hydroxide, a strong base and corrosive, in 50ml of water to observe the change in temperature of the solution. At room temperature, sodium hydroxide is a white crystal-like odorless solid that absorbs moisture from the air. When dissolved in water or used to neutralized acid, it unleashes substantial heat which undoubtedly the predominant catalyst for the change in the energy. The heat that is produced by sodium hydroxide is sufficient to ignite combustible substances
MATERIALS AND METHODS: Before the acetic acid solution could be titrated with sodium hydroxide (NaOH), the actual concentration of NaOH needed to be determined. By way of standardization, the actual concentration of NaOH was established, to account for the fact that the solid is not pure and for its tendency to react with carbon dioxide in the air. A 50 mL burette (±0.01 mL, Kimax) was rinsed thoroughly, twice with reverse osmosis water, and then twice with approximately 5 mL of ~0.25 M NaOH solution
Temperature Changes During the Addition of Sulphuric Acid and Sodium Hydroxide Solution Aim To investigate the temperature changes during the addition of sulphuric acid and sodium hydroxide solution. Introduction In this experiment we are using sodium hydroxide, sodium hydroxide, sulphuric acid. We are trying to find out how much acid it takes to neutralise alkaline. But there are many things that could effect my final result and I think that the main thing will be measuring the acid
trying to find out how much acid it takes to neutralise a base to form a neutral solution. I will use one molar of Nitric Acid as the acid and one molar of Ammonium Hydroxide as the base. So this will be a 1:1 ratio. (Molarity = how many molecules of the acid or alkali per 1000 cm3 (1 litre) of water.) Nitric Acid + Ammonium Hydroxide à Ammonium Nitrate + Water ----------------------------------------------------------- HNO + NH OH NH NO + H O Ionic bonding must take
which the galactose subunit is removed from lactose and joined to a molecule of fructose. Isomerization of lactose can be accomplished using chemical or enzymatic methods. Chemical methods employ an alkaline catalyst, such as sodium hydroxide or potassium hydroxide, in combination with a complexing agent, such as borate or aluminate, that will attach to lactulose and precipitate as an insoluble complex from the reaction system, thus shifting chemical equilibrium in favor of the formation of the
the alkalis. Diagram [IMAGE] Method ====== 1. I will first measure out 20ml of 2M Hydrochloric acid and pour it into the glass beaker. 2. Then I will measure the starting temperature. 3. Then I will out 20ml of 2M Sodium hydroxide add it into the
* A Thermometer * Universal Indicator * 25ml Hydrochloric Acid * 25ml Sodium Hydroxide Method/Plan of the experiment: First of all, I will set up the apparatus as the diagram shows: Then, I will measure out the acid and alkali using the measuring cylinder. Once I have done that, I will pour the 25ml of Hydrochloric Acid in to the conical flask. I will also pour the 25ml of Sodium Hydroxide into the burette, and adding 1cm cubed of alkali at a time into the conical flask, I will
of Lithium was used, in my case it was 0.11g. At the end of this experiment, the volume of Hydrogen gas I collected was 185cm³. Then using the solution of lithium hydroxide made from experiment one, I used it in the titrating experiment, to find out the total volume of Hydrochloric acid used to titrate the lithium hydroxide. RESULTS TABLE Experiment Initial Volume ( cm³) Final Volume ( cm³) Total volume Of HCl used ( cm³) Rough 0.2 30.3 30.1
molecule. Succinic acid can be completely neutralised by sodium hydroxide. The indicator most suitable for this experiment is phenolphthalein, it is colourless in acids and pink in alkalises. The half way stage is about pH 9.3, this is when it will either change from colourless to a very pale pink or from pink to colourless. To determine the relative formula mass of succinic acid I am going to do a titration against sodium hydroxide. The equation for the reaction is given below. To make the
provides a durable, decorative, glossy appearance. If rusting continually takes place the car becomes unsafe. When water and oxygen come in contact with the metal of the car surface, several redox reactions happen. The oxygen is reduced to hydroxide ions and iron is oxidized to Fe2+ ions which pass into solution. More reactions happen which ultimately produce rust - Fe2O3H2O. The components of car paint There are three components of car paint, each one has different roles: * The pigment
solution: H2O → H (+) + OH (-) During the electrolysis process, the positive hydrogen ions move towards the cathode and the negative hydroxide and sulphate ions move towards the anode. At the cathode the hydrogen ions gain an electron. They are discharged and are converted into hydrogen gas: 2H (+) + 2e (-) → H2 At the anode, the hydroxide, not the sulphate ions are discharged. Water and oxygen gas are formed: 4OH (-) → 2 H2O + O2 + 4e (-) The hydrogen gas can be collected
Background information As explained before, neutralisation happens between an acid and a base. Neutralisation is the formation of water from hydrogen and hydroxide ions H30+(aq) + OH-(aq) à 2H20(aq) According to ArrheniusÂ’ theory ‘neutralisation occurs because equal mols of hydrogen ions in the acid are equal to the mols of hydroxide ions in the base so the two react completely to form waterÂ’*1. Neutralisation of HCl and NaOH: NaOH(aq)        +         HCl(aq)            Â
Apparatus ========= v Empty plastic yoghurt cup v thermometer v Hydrochloric Acid v Sodium Hydroxide v Two measuring cylinders [IMAGE] Diagram ======= [IMAGE] [IMAGE] 30ml³ Hydrochloric acid [IMAGE] [IMAGE]Thermometer [IMAGE][IMAGE] Measuring Cylinder [IMAGE] Plastic cup [IMAGE] [IMAGE] 30ml³ Sodium Hydroxide Method ====== First of all we decided to use a plastic cup because it was easy to wash off the mixture
producing an equilibrium to form ethyl ethanoate and water. CH3COOH(aq) + C2H5OH(aq) ó CH3COOC2H5(aq) + H2O(l) Following the method as detailed, I conducted experiment 4 and these results were obtained: Titration Trial Volume of Sodium Hydroxide Neutralised (cm3) 1 7.65 2 7.75 3 7.80 4 7.70 5 7.75 μ 7.75 To calculate Kc, the concentrations of each reactant must be calculated from the point of equilibrium at which the titration was taken. Therefore