experiments to determine the exact concentration of a 0.1M sodium hydroxide solution by titration (Lab Guide pg.141). QUESTION The question that was proposed for investigation was: Can the exact concentration of 0.1M sodium hydroxide solution be determined by titration (Lab Guide pg. 141)? BACKGROUND DISCUSSION For this experiment we used titration to standardize the exact concentration of NaOH. Titration is the process of carefully adding one solution from a buret to another substance in a flask until all
Energy In this lab, we dissolved Sodium hydroxide, a strong base and corrosive, in 50ml of water to observe the change in temperature of the solution. At room temperature, sodium hydroxide is a white crystal-like odorless solid that absorbs moisture from the air. When dissolved in water or used to neutralized acid, it unleashes substantial heat which undoubtedly the predominant catalyst for the change in the energy. The heat that is produced by sodium hydroxide is sufficient to ignite combustible substances
Temperature Changes During the Addition of Sulphuric Acid and Sodium Hydroxide Solution Aim To investigate the temperature changes during the addition of sulphuric acid and sodium hydroxide solution. Introduction In this experiment we are using sodium hydroxide, sodium hydroxide, sulphuric acid. We are trying to find out how much acid it takes to neutralise alkaline. But there are many things that could effect my final result and I think that the main thing will be measuring the acid
atomic mass of lithium. 1) In the first method the RAM (Relative atomic mass) of lithium is determined by the Volume of hydrogen gas produced. 2) In the second method the RAM of lithium is determined by titrating the lithium hydroxide produced. To some extend, I think that the first method is the most practical and less complicated, because the less calculations has to be done. Hence it is more easer to measure the volume of hydrogen gas. Test-1 My mission
INTRODUCTION ============ Aim- to investigate the effect that concentration has on a reaction on these factors: * Temperature rise * Heat evolved * Heat given off due to the neutralization between Hydrochloric Acid and Sodium hydroxide solution. Neutralization takes place when acids react with substances called bases. When they react their acidity is cancelled out, and the reaction always produces a salt and water. The base can be soluble (when called an alkali) or insoluble
acid to form a neutral solution; which contains salt and water. Acid + Base Salt + Water --------------------------- In my experiment I am trying to find out how much acid it takes to neutralise a base to form a neutral solution. I will use one molar of Nitric Acid as the acid and one molar of Ammonium Hydroxide as the base. So this will be a 1:1 ratio. (Molarity = how many molecules of the acid or alkali per 1000 cm3 (1 litre) of water.) Nitric Acid + Ammonium Hydroxide à Ammonium Nitrate + Water
Acid * 25ml Sodium Hydroxide Method/Plan of the experiment: First of all, I will set up the apparatus as the diagram shows: Then, I will measure out the acid and alkali using the measuring cylinder. Once I have done that, I will pour the 25ml of Hydrochloric Acid in to the conical flask. I will also pour the 25ml of Sodium Hydroxide into the burette, and adding 1cm cubed of alkali at a time into the conical flask, I will record the temperature of the solution made by the two substances
molecule. Succinic acid can be completely neutralised by sodium hydroxide. The indicator most suitable for this experiment is phenolphthalein, it is colourless in acids and pink in alkalises. The half way stage is about pH 9.3, this is when it will either change from colourless to a very pale pink or from pink to colourless. To determine the relative formula mass of succinic acid I am going to do a titration against sodium hydroxide. The equation for the reaction is given below. To make the
the solution inside its container the best. I have chosen the glass beaker and the polystyrene cup because I have found that these two containers are resistant to any sort of corrosion that might occur whilst I will be using the acid and the alkalis. Diagram [IMAGE] Method ====== 1. I will first measure out 20ml of 2M Hydrochloric acid and pour it into the glass beaker. 2. Then I will measure the starting temperature. 3. Then I will out 20ml of 2M Sodium hydroxide add
fixed amount of Lithium was used, in my case it was 0.11g. At the end of this experiment, the volume of Hydrogen gas I collected was 185cm³. Then using the solution of lithium hydroxide made from experiment one, I used it in the titrating experiment, to find out the total volume of Hydrochloric acid used to titrate the lithium hydroxide. RESULTS TABLE Experiment Initial Volume ( cm³) Final Volume ( cm³) Total volume Of HCl used ( cm³) Rough 0.2 30.3
Investigating a Neutralisation Reaction Between Hydrochloric Acid and Sodium Hydroxide To investigate a neutralisation reaction I must know all the factors that affect it in order to investigate in this. Here are all the factors; Temperature - This will defiantly affect an exothermic or endothermic reaction. Concentration - If the solution is made more concentrated it means it contains more particles of reactant, therefore more collisions are likely and an result of this is that the
glossy appearance. If rusting continually takes place the car becomes unsafe. When water and oxygen come in contact with the metal of the car surface, several redox reactions happen. The oxygen is reduced to hydroxide ions and iron is oxidized to Fe2+ ions which pass into solution. More reactions happen which ultimately produce rust - Fe2O3H2O. The components of car paint There are three components of car paint, each one has different roles: * The pigment provides a barrier to protect
Background information As explained before, neutralisation happens between an acid and a base. Neutralisation is the formation of water from hydrogen and hydroxide ions H30+(aq) + OH-(aq) à 2H20(aq) According to ArrheniusÂ’ theory ‘neutralisation occurs because equal mols of hydrogen ions in the acid are equal to the mols of hydroxide ions in the base so the two react completely to form waterÂ’*1. Neutralisation of HCl and NaOH: NaOH(aq)        +         HCl(aq)            Â
========== 1. The pH meter is calibrated, using a buffer solution of accurately known pH. 2. 20.0cm3 of 0.10M ethanoic acid was pipetted into a conical flask. 3. 0.10M sodium hydroxide solution was titrated using phenolphthalein as indicator, until the solution was just turned pink. 4. A further 20.0cm3 of the same ethanoic acid solution was added to the flask and was mixed thoroughly. 5. The pH of the resulting solution was determined. Result: ======= Volume of NaOH used
producing an equilibrium to form ethyl ethanoate and water. CH3COOH(aq) + C2H5OH(aq) ó CH3COOC2H5(aq) + H2O(l) Following the method as detailed, I conducted experiment 4 and these results were obtained: Titration Trial Volume of Sodium Hydroxide Neutralised (cm3) 1 7.65 2 7.75 3 7.80 4 7.70 5 7.75 μ 7.75 To calculate Kc, the concentrations of each reactant must be calculated from the point of equilibrium at which the titration was taken. Therefore
Discussion Unknown Solution 1 I believe that the first unknown solution is made up of molecular compounds. This is because the solution had very little conductivity, meaning there was not an equal amount of ions broken down in the solution. The solution had no scattering, which means the molecular compounds were fully dissolved in their solvent, which was not water. When tap water was added to solution 1, the color changed from green to blue. If water was the original solvent, we would not see this
Citric Acid Problem ------- I have been set the task of determining the concentration of a sample of citric acid, using only a 1.0 M solution of sodium hydroxide and any laboratory glassware that is required. I have also been given the RMM of citric acid as 210g and I have been told that one mole of citric acid will react with 3 moles of sodium hydroxide. My Experiment ------------- Using this information I have determined that the best way to conduct this experiment is to do a titration
Investigation into the solubility of Calcium Hydroxide Ca(OH)2 Planning ======== Calcium Hydroxide is a strong base which is alkaline in water. Lime water containing approximately 0.015 mol dm-3 will be used for the titration. HCl will be used also, and has a concentration of 0.3 mol dm-3 . Aim: The aim of the investigation is to determine the solubility of Calcium Hydroxide by calculating the concentration by means of a titration. Plan: Clamp stand Burette [IMAGE][IMAGE][IMAGE]Titration
Alkaline solutions have a pH value greater than 7. Alkaline solutions feel soapy and are corrosive. Examples of bases and alkalis: NAME FORMULA DOES IT DISSOLVE IN WATER ALKALI OR BASE FOUND IN/USED FOR Copper oxide CuO No Base Sodium hydroxide NaOH Yes Alkali pH 13 Used to remove grease from ovens & drains. Used to make soap Ammonia NH3 Yes Alkali pH 10 The main active ingredient in household cleaning fluids Calcium hydroxide Ca(OH)2
Chitosan is a cationic copolymer of glucosamine and N-acetylglucosamine (Mourya, Inamdar,&Tiwari, 2010).Due toits non-toxicity, biodegradability, biocompatibility, bioadhesivity, antimicrobial activity and physicochemical and biological properties, chitosan can be applied in a variety of fields. However, the poor solubility in water and most common organic solvents limits its applications (Dash, Chiellini, Ottenbrite, &Chiellini, 2011).According to the literature (Du & Hsieh, 2008; Mourya, Inamdar