The Gas Laws

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I can draw three characteristics from properties that gases have. Compressibility, expandability, and the way in which gases occupy spaces more than liquids or solids in a taken form. A tremendous example of this characteristic in which we use to describe compressibility in gases, is the way in which a 911 Porsche sports car works. A 911
Porsche sports works off an internal combustion engine(normally v8/ but in this case I'm talking about a particular four-stroke), in which “compresses gases” just as I was talking about. In order to operate, the piston in the engine pulls out of the cylinder to create a vacuum which draws a mix of gasoline vapor oxygen into the driving cylinder compartment. Then eventually seconds later, the piston then rotates pushing back into the cylinder compressing the gasoline/air type of mixture to a new volume, compared to the volume it had when the piston was rotated to the top of its socket. The typical car has a 9 to 1 compressibility ratio, but this porsche has about 7 to 1 compressibility, which can mean the gas to air mixture in the cylinder is compressed by a factor of 7. The second
Property I would like to outline in gases is expandability. Anyone who has walked into a bathroom where many people have just taken a number 2, have experienced the face that gasses expand to fill their container, as the air in the disgusting bathroom becomes filled with terrible odors of waste. Just as people smell during a formula 1 race event, characteristic odor of C2H5OH Ethanol rapidly diffuses through the race track as it makes it way through the cars and also is on the track of the pit stops. Gases expand to fill their containers, so it is safe to say that volume of a specific gas can be equal to the volume of it...

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...hing is represented in moles, therefore ideal gas law must be employed to solve the volume or mass of bass involved in the reaction. For example, if I wanted to calculate the volume of NO2 produced from combustion of 100 g of NH3, by reaction 4NH3 +7O2=4NO2 + 6H2O. It could be solved by 100 g NH3 times 1 mol NH3/17.034gNH3= 5.871 mol NH3. But on another hand the chemical reaction is given in terms of moles, not grams, so therefore the ideal gas law must be employed to solve the volume or mass of the gas involved in the reaction. In using the same example as before, if I wanted to continue out the process: there is a 1 to 1 molar ration of NH3 to NO2 in the balanced combustion reaction, so 5.871 mol of NO2 will be formed. Using the PV=nRT to solve for the volume at zero degrees (273.15 K) and 1 atm using the gas law constant R=008206 times atm times K-1 times mol -1.

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