The Effect On Chips In Salt Solutions
Group Information
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1. Length Of Pieces = 4cm
2. No Of Pieces Per Test Tube = 1
3. Solutions Used = All (Distilled Water, 0.1 - 0.4M and 0.6M
(solutions between 0.1 - 0.4 increased by 0.1 each time)
4. Amount Of Solution = 10ml
Personal Information
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P6 a I) In our experiment to study Osmosis I think that the 0.6 M
solution will give the chip a rubbery effect because in the 0.6 M
solution the salt will absorb all of the moisture out of the chip. The
0.4 M solution will have a large effect on the chip but not as large
as the 0.6 M solution. I think that the 0.3 M solution will be
balanced so the chip will stay as it is. The 0.2 M solution will make
the chip bulkier because the chip will absorb the water out of the
solution. The 0.1 M solution will have more effect than the 0.2 M
solution but not as much as the effect that Distilled water will have
on the chip because distilled water has no salt strength, this means
that none of the cells will shrink however they will grow in size
causing them to gain weight.
P6 a II) The varying factor will be the strength of the salt solutions
used which are Distilled Water, 0.1 - 0.4M(solutions between 0.1 - 0.4
increased by 0.1 each time) and 0.6M.
.
P6 a III) The controlled factors will be the size of the potato and
the amount of salt solution used.
P6 b I) We will aim to get two different sets of results.
P6 b II) The thing that we will measure will be the weight of the chip
before and after the experiment.
Results
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1st Set
Solution
1st Weight
2nd Weight
Gain/Loss
Distilled Water
help give a better idea of how the rate of osmosis is affected by the
We were then to make a base solution of 0.7 M NaOH. In order to standardize
The Effect of Solute Concentration on the Rate of Osmosis Aim: To test and observe how the concentration gradient between a potato and water & sugar solution will affect the rate of osmosis. Introduction: Osmosis is defined as, diffusion, or net movement, of free water molecules from high to low concentration through a semi-permeable membrane. When a substance, such as sugar (which we will be using in the experiment we are about to analyse), dissolves in water, it attracts free water molecules to itself, and in doing so, stops them from moving freely. The effect of this, is that the concentration of (free) water molecules in that environment goes down. There are less free water molecules, and therefore less water molecules to pass across a semi-permeable membrane, through which sugar molecules and other molecules attached to them are too big to diffuse across with ease.
to the marble chips. I will have 30 ml of mixture and split it in to
In my experiment, I will use an overall volume of 50 cm³ of 2moles of
concentrations of 10mM, 20mM and 40mM. What this finding tells us is that our manipulation
The experiment is aimed at giving a better understatement of osmosis process and the different conditions in which osmosis occurs.
We take one potato and cut from it three even potato chips. These potato chips will never be the same weight as we had to cut them ourselves and it is too inaccurate. So we decided to calculate the percentage gain/loss as this would mean that the measurements are all on the same scale. We then weighed the potato chips on a very sensitive weighing scale. These weighing scales can weigh things to a hundredth of a gram so our measurements are very accurate.
Experiment to Find the Reaction of Potato Chips in a Salt Solution. Aim: to find a reaction of potato chips in a salt solution. Hypothesis: I predict that the potato will change in mass. The difference will occur in accordance to the difference of concentration of the salt solution each potato chip is submerged in.
Investigating the Effect of Sugar Solution on the Weight and Size of Potato Cells Aim: To investigate whether the different concentration of sugar solution will affect the weight and size of the potato cells. General background information: Osmosis is defined as the movement of water or any other solution's molecules from an area in which they are highly concentrated to a region in which they are less concentrated. This movement must take place across a partially permeable membrane such as a cell wall, which lets smaller molecules (E.g. water) through but does not allow larger solute molecules to pass through. The molecules will continue to diffuse until the area in which the molecules are found to reach a state of equilibrium, meaning that the molecules are equally distributed throughout the cell, with no area having a higher or lower concentration than any other hence equal. Hypothesis/prediction: For this particular investigation I believe that the lower the concentration of the sugar solution in the test tube the mass of the potato will be greater and the longer the potato cells will be.
== = This experiment is based on the concept of Osmosis. Osmosis is the diffusion of water molecules from a region of high water concentration to a low water concentration through a semi permeable membrane (in this case, the cell potato cell membrane). The cell walls of the potato cells are semi permeable meaning that water molecules (which are small) can fit through but other bigger molecules such as glucose cannot pass through. The water molecules can flow both ways through the membrane, letting molecules both in and out.
Osmosis in Potato Tubes Osmosis: Osmosis is the movement of water molecules through a semi-permeable membrane from a high concentration to a low concentration. Diagram: [IMAGE] [IMAGE] Aim: To see the effects of different concentration of sugar solution on Osmosis in potato tubes. Key factor: In the investigation we change the sugar solution from: 0%-10%-20%-30%-40%-50% this is the independent variable; the dependant variable is the change in mass. Prediction: I predict that all the potato tubes in pure water or low concentration sugar solution will swell because water enters their cells by osmosis.
I blanked it with 2 cm³ water, 1 cm³ amylase and 3 drops of iodine.
The Effect of Salt Solution Concentration On The Mass Of Potatoes Introduction = == == == ==
second test tube also add 6 mL of 0.1M HCl. Make a solution of 0.165