RESEARCH TOPIC MEMO
TO: teacher name
FROM: student name
COURSE:
DATE:
SUBJECT: Functioning of the Suction Cup Lifter
This memo’s primary objective is to begin to develop a research project on the operation of the suction cup lifter. I chose this topic in order to be able to gain a better understanding of how the suction cup works. I also chose this topic in order learn how the structure and properties of the suction cup and how its processing interactions affect the selection and use of the particular material used in its manufacture. I also chose it to understand better and show why it is relevant to the workings of factories and construction companies.
This research project will seek to understand better the functioning of the suction cup,
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When pressure is applied to the suction cup, the air is expelled underneath the cup. The pressure in the suction cup is eliminated and thus creates a vacuum. The vacuum seals the cup tight onto the workpiece. The pressure difference is attained by connecting the suction cup to a vacuum generator, which sucks out the air within the space which is between the suction cup and the workpiece. When the cup is in contact with the surface of the workpiece, no air can enter it from any sides; hence, a vacuum is generated. When removing the suction cup, the air pressure on the outside becomes lower than that inside the cup. Gravity and friction are the main forces that create the perfect conditions for the suction cups to work. Gravity pushes molecules in the air towards the earth, creating an atmospheric pressure of approximately 14.7 pounds for every square inch at the sea level. A good suction cup on a smooth surface causes the pressure to be applied on the cup, pushing it down onto the surface where Friction keeps the cup from moving sideways. The force holding the suction cups goes proportionally with the change in the atmospheric pressure and the pressure which is inside the …show more content…
It is, however, not possible to specify correct values of the friction coefficient between the suction cup and the workpiece. It has to be determined accurately through trials with different conditions of the workpiece surface such as when it is rough, dry or moist. It can also be determined by the properties of the suction cup such as its shape suction cup material. These properties have an effect on the friction coefficient.
The force that is required to remove the suction cup is given by:
F= A×ΔP where: F represents the holding Force A represents the surface area covered by the cup; area under the vacuum P is the atmospheric pressure; pressure outside the cup
However, this formula operates under the assumption that the external diameter does not change after the cup has been pulled off. The formula assumes that there are no air leaks between the cup and the surface. It also assumes further that the force used to remove the cup is applied perpendicularly, that is, the cup does not slide sideways when been removed.
The holding force, however, depends on its effective diameter. The condition of the workpiece is also vital for the holding force that the vacuum system will generate. The formula below helps in determining the diameter that is
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Torque= Force x radius , since the radius is half the diameter , T=F x D/2
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The size of this depends on the mass of the object and the size of the
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