Spiral Separator Lab 4
Materials:
The equipment and materials used are as follows:
Scale PPE Spiral Separator Magnetite/Silica samples
Introduction:
Wet spiral separators are devices utilized to separate solid components in slurry. The slurry must contain constituents based upon a combination of a solid’s particle density and the particle's hydrodynamic properties. The device consists of a spiral tower with a sluice wrapped around from which slots or channels are placed in the base of the sluice to extract solid particles that have come out of suspension.
The larger and heavier a particle, attains for it to sink to the bottom of the sluice faster. This allows the particle to experience more drag from the bottom, and so it moves toward
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Recorded the volume of water used. Filled the collection tank until the red float rose and added at least 200 mL more. Plugged the unit in and pump turned on. Adjusted the black 4-headed knob until the water flow was below the lip of the spiral funnel. Prepared a 500 gram sample and two 1000 gram samples of 10% magnetite and 90% sand. Used a graduated cylinder, determined the specific gravity of both magnetite and sand. Added one of the 1000 gram dry samples to the top of spiral where water is coming out of the distributor. Allowed the sample to circulate until steady state was reached. Once achieved steady state, adjusted the yellow gate at the bottom of the spiral to get efficient separation from the two outlets. Collected a sample from each of the outlets and separated the denser material (heads) from the lighter material (tails). Then quantitatively transferred the heads and tails to a pan and measured the mass of solids plus …show more content…
This is most likely due to a sampling error caused by the pump delivery fluctuations. Therefore the pump never did achieve a steady state condition. Grade recovery would show up mainly in the magnetite specific gravity. All it would have taken was a minor fluctuation in the flow regime to homogenize the sample because the collection time required for the sample was longer than for the silica.
The spiral concentrator had several variables involved with the control of ore grade. First begins with the percent of solids, compared to the water flow. The effects of this were seen in the first and second samples, in which the pump was fluctuated by placing a clamp on the hose from the pump on top of the spiral separator. As the water was pumped, the first sample was added and it appeared to develop a clog at the bottom. The water was unable to carry the lighter particles as far up the outer radius. This caused the silica to be more centered and the stream of the magnetite to be thinner and more
Each subsequent trial will use one gram more. 2.Put baking soda into reaction vessel. 3.Measure 40 mL vinegar. 4.Completely fill 1000 mL graduated cylinder with water.
Compress the safety bulb, hold it firmly against the end of the pipette. Then release the bulb and allow it to draw the liquid into the pipette.
We used the pipette filler and filled the glucose rinsed pipette to add 10ml of 10% of glucose in test tube 0.
2. Drop a gummy bear into each of your prepared beaker or cup and place the beaker or cup
· Rinse out mixture in flask and leave water running to get rid of the
sample using a triple beam balance. Then, fill the small chamber about halfway with water and measure
Separations are important techniques in chemistry that are used to separate various components of a mixture. They are carried out by mixing two immiscible liquids containing certain solutes together in a separatory funnel, allowing them to separate, then extracting the distinct layers that form. The ratio of the concentration of solute present in the upper layer to the concentration in the lower layer is called the partition coefficient. The efficiency of a separation is described by this partition coefficient. If the coefficients for the two layers are largely different, then the separation can be carried out in a single step. If they aren’t, a more complex process is necessary.1,2 Countercurrent chromatography is a technique used carry out separations in these kinds of cases. It uses a continuous liquid-liquid partitioning process to streamline the usual extraction procedure.
3. Add on of the following volumes of distilled water to the test tube, as assigned by your teacher: 10.0mL, 15.0mL, 20.0mL, 25.0mL, 30.0mL. (If you use a graduated cylinder, remember to read the volume from the bottom of the water meniscus. You can make more a more accurate volume measurement using either a pipette or a burette.)
Attach a buret clamp (located under the hood) to a ring stand. b. Rinse the burets three times with approximately 10 ml of deionized water. Tilt and rotate the buret in an almost horizontal position (don't let the water spillout!) to rinse the entire inside wall. Allow about 5 ml of water to run through the buret tip on the last rinse. c. Pre-rinse one buret with approximately 5 ml of your Unknown acid solution. Again, rotate the buret to rinse the entire inside wall of the buret as above. d. Clamp the buret in one side of the buret clamp. Place a white piece of paper labeled "Unknown acid" under this buret. Drain any remaining pre-rinse acid solution into a beaker labeled "waste solution". e. Fill this buret with your Unknown acid solution to the zero mark or slightly below it (Not above the zero mark). Make sure the tip of the buret is completely filled and contains no air bubbles. f. Pre-rinse the second buret with approximately 5 ml of standard base solution. Clamp the buret in the other side of the buret clamp. Place a white piece of paper labeled "Standard NaOH solution" under the buret. Drain remaining prerinse NaOH solution into the waste solution beaker. Fill this buret with standard
The hypothesis that was formed in this experiment was that decantation and distillation were the techniques that would be successful in separating the three layered substances. The oil on top of the mixture was to be decanted solely, and the salt and sand layers would be distilled and separated together on filter paper on top of boiling hot water. The reason that the oil is decanted is because it doesn’t mingle with the salt and sand layers, and in addition it was the top layer, which was thought to have been easy to separate first. And as for the sand and salt, sand doesn’t mix and dissolve in water compared to salt, which does in fact dissolve, so distillation was thought to be the proper solution to separating the two
Once the mixture had been completely dissolved, the solution was transferred to a separatory funnel. The solution was then extracted twice using 5.0 mL of 1 M
I shall add water as that is the only way I can find out how
with 0.0M (distilled water) and go up by 0.1M until I reach 1.0M and I
of distilled water. For the 1M solution I added 50 cm3 of HCl and 50
Weigh out two 0.100 g. samples of the product and put each into a test