Sensor Project
Method:
· I set up the circuit shown in my diagram above.
· I then recorded some results for my preliminary experiments at
various temperatures.
· I then started taking results at 5oC intervals starting at 45oC and
ending my results at 85oC.
· I then repeated the experiment 3 times.
· I changed the ohmmeters sensitivity.
· I recorded the resistance of the thermistor at 1oC intervals
starting at 35oC to 40oC.
· I repeated this new experiment 3 times as well.
Physical Principals and Equations:
As the temperature of the water bath increases then the resistance of
the thermistor decreases. This is for a negative temperature
coefficient thermistor.
The thermistor must have a lower resistance than the water otherwise
the water's resistance will be recorded and not the thermistor's
resistance.
I will use the equations:
V = I x R voltage = current x resistance
I = K x V current = constant x voltage (I is proportional to V)
V = E - I x R potential difference = emf - current x internal
resistance
Calculations and Graphs:
I think that my graphs will look like this:
Why I chose this project:
I am going to set up this circuit because I thought that it would be a
useful sensor to create. With this sensor and the results that I have
obtained from it, you will be able to use it as a thermometer. To do
this you will only have to look at the graphs that I produced and read
off the relevant section. So if you set up my circuit then you can
take any substance and it can be at any temperature between the
temperatures of 45oC - 85oC, then read off the resistance of the
thermistor, read the temperature for that specific resistance off the
graph and you will know how hot it is. This could be useful if you
wanted to know how hot you food and drink is and also the temperature
The purpose of this lab was to calculate the specific heat of a metal cylinder
From looking at Sources F, M and E and my own knowledge I can clearly
(Graph below would be posted using the PowerPoint for students to see before open discussion
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- Temperature was measured after and exact time i.e. 1 minute, 2 minutes, 3 minutes.
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V(voltage) I (current) Therefore, I = V R Therefore, if V is constant, in order to increase I, R must decrease.