Rearranging Letters Experiment
This investigation is set in order to find a formulae to solve how
many arrangements you can get for any word, no matter how many letters
or how many letters are repeated. First of all a formulae will be
found for finding out how many arrangements can be found for the name
LUCY. When this is found, I will then find out how many arrangements
one can get from the name EMMA. After finding how many arrangements
there are, I will put them into a formulae and see if there is any
relation between the first part and the second part of this
investigation. Once I have tried to make a link between these
sections, I will move onto part 3, and decipher a way that you can
work out how many arrangements there are for any word.
Part 1 - Lucy
First I am going to investigate how many different arrangements in the
name Lucy, which has no letters the same.
LUCY, LUYC, LYCU, LYUC, LCYU, LCUY, ULCY, UCLY, UYLC, ULYC, UCYL,
UYCL,
YCUL, YUCL, YULC, YLCU, YLUC, YCLU, CYLU, CYUL, CUYL, CULY, CLUY,
CLYU.
Here as you can see there are 24 different ways of arranging the name
Lucy. A quicker way of writing this down would have been to see how
many arrangements you could make by leaving L as the first letter.
There are 6 when structured like this. After you have all the L ways
are worked out, then just times that number (6) by 4, as there are 4
letters in the word. This makes 24, in which are how many arrangements
of the word there is. So now I have to work out is there a way of
breaking 24 down into formulae to create how many arrangements there
are of the word.
4 letters, no letters repeated. Half or 24 is 12, 4 into 12 is three…
Therefore putting this together would make, 4x3=12 x 2=24 = correct
answer. This method of calculation is called factorial.
12. If d = 3 + e, and e = 4, what is the value of (20 - d) + e
have no labels, 1 label, 2 labels and 3 labels. Once I have done this
In the experiment “ Talking to plants “ from Mythbusters, potential problems include the use of greenhouses with no sound insulation, a non-homogeneous location and the use of only one specie to infer on a population. In another scientific study, researchers chose to use “ a noiseless growth chamber to prevent any effects from extraneous noise “ and the use “ growth chambers under continuous light at 28 c and 65-75% relative humidity “ in order to maintain a homogeneous location for all plants during the experiment (Jeong et al., 2008) . This helped further explain the findings because with the use of noiseless chambers you can assure that the only noise that the plant was receiving was the one given in the treatment and a valid conclusion
The Screwtape Letters are a fictional series of letters compiled into a book and written by the highly acclaimed apologist and author, C.S. Lewis. The Letters discuss topics such as salvation, the Christian lifestyle, depression, love, and many other subjects that are pivotal to the way we live, think, and interact with others and the world around us.
A former Yale psychologist, Stanley Milgram, administered an experiment to test the obedience of "ordinary" people as explained in his article, "The Perils of Obedience". An unexpected outcome came from this experiment by watching the teacher administer shocks to the learner for not remembering sets of words. By executing greater shocks for every wrong answer created tremendous stress and a low comfort levels within the "teacher", the one being observed unknowingly, uncomfortable and feel the need to stop. However, with Milgram having the experimenter insisting that they must continue for the experiments purpose, many continued to shock the learner with much higher voltages.The participants were unaware of many objects of the experiment until
Problem Statment:You have to figure out how many total various sized squares are in an 8 by 8 checkerboard. You also have to see if there is a pattern to help find the number of different sized squares in any size checkerboard.Process: You have to figure out how many total different sized squares you can make with a 8x8 checkerboard. I say that there would be 204 possible different size squares in an 8x8 checkerboard. I got that as my answer because if you mutiply the number of small checker boards inside the 8x8 and add them together, you get 204. You would do this math because if you find all of the possible outcomes in the 8x8, you would have to find the outcome for a 7x7, 6x6, 5x5, 3x3, and 2x2 and add the products of
8. Repeat from step 4 twice more so you end up with three results for
Six items is the total number of items because the brain can better process it.
The Asch and Milgram’s experiment were not unethical in their methods of not informing the participant of the details surrounding the experiment and the unwarranted stress; their experiment portrayed the circumstances of real life situation surrounding the issues of obedience to authority and social influence. In life, we are not given the courtesy of knowledge when we are being manipulated or influenced to act or think a certain way, let us be honest here because if we did know people were watching and judging us most of us would do exactly as society sees moral, while that may sound good in ensuring that we always do the right thing that would not be true to the ways of our reality. Therefore, by not telling the participants the detail of the experiment and inflicting unwarranted stress Asch and Milgram’s were
cuatro y medio (four and a half): in the latter, the first string is attached to a peg
Above is my original data. In the graph, it can be seen that there are
Children can enhance their understanding of difficult addition and subtraction problems, when they learn to recognize how the combination of two or more numbers demonstrate a total (Fuson, Clements, & Beckmann, 2011). As students advance from Kindergarten through second grade they learn various strategies to solve addition and subtraction problems. The methods can be summarize into three distinctive categories called count all, count on, and recompose (Fuson, Clements, & Beckmann, 2011). The strategies vary faintly in simplicity and application. I will demonstrate how students can apply the count all, count on, and recompose strategies to solve addition and subtraction problems involving many levels of difficulty.
with four words in each, 6 x 4 =24. On the second word list use the
By using combinations from the above – But this approach has to be made with caution, because confusion can appear in the message.
and 8 can be written as 2 , while 5, 6, and 7 can be written using some