Mole Ratios Lab Report

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Recommended: Laws of conservation of mass

Introduction:
A balanced chemical equation has reactants and product that has to represent a formulae. The amount of each element, number needs to be the same on either side of the equation. (E.g., HCl(aq)+NaHCO3(s) reacts to produce NaCl(aq)+H2O(I)+CO2(g)). This helps us view the study of the Law of Conservation of Mass, and how it works in this equation.
The calculation for formula, mass helps us to determine if you need to convert grams to a particular substance to moles, from a product. Moles are numbers that are in front of formulae. E.g., 6NaCl(aq), 6 is the mole for this compound. A mole would help you balance a skeleton equation, and also allows you to calculate how many moles are needed to take part in a chemical reaction.
In the laboratory experiment, we are investigating the following equation and …show more content…

In the data (Q2) shows that we have approximately 0.0416mols of NaCl(aq), and also approximately 0.0416 of NaHCO3. In the end the yield for NaCl(aq)(product), we got was 3.077%. This percent is lower because of the incident that acquired during the lab. Which leads to possible errors that can happen during the lab. The percent was lower them hundred percent was because of the spill of the solution that happen while working on the lab. We lost a lot solution which affected the amount of mole for NaCl(aq) and the yield drastically from looking at the calculation. Another possible error can be when you are cooking the solution and didn’t get to evaporate all the water that is still visible in our eye, it can cause your calculation to be incorrect and less product you are looking for in the end. Last error can be when the electrical balance can malfunction during your experiment or it doesn’t work or possibly broken. These are some of the possible errors that can happen in the lab that can affect the data

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