How to use order of operations

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How to use order of operations. What does any kind of order have to do with math? It’s just left to right isn’t it? Wrong, the order of operations is a specific method to figuring out the correct answer to certain problems. For those of you who do not realize what I am yammering on about, this procedure piece is about the order of operations. The order of operations is a method used to ensure that a group of people gets the correct answer without dispute, the order of operations is extremely useful. Without knowing the order of operations tell me, does this problem look sensible? 67-9(6-1)+48/ ((9x (5+2)-7’ Didn’t think so. The order of operations works like this: First anything in the parentheses, then we do the exponents/roots, then any multiplication and division- which is done in that order, then we do Addition and Subtraction- in that order as well. To explain this, we will solve the problem above: Step 1. The first thing you do in the order of operations is to do anything listed in parentheses, but you must also keep in mind everything else. So the first set we do is (5+2), even though it is the last set, addition comes first on the order of operation list. So, (5+2)= 7 right? Right, keep that in mind. Now we do the first set of parentheses, which is (6-1) which is 5. So replace both of those sets with (5) and (7) in that order. Step 2. The next step is to get rid of those nasty square roots and exponents. So, first we do the square root of 9, which is 3. Then we perform the sacred exponent figuring. So 7 squared (7’) is 49. So by now the expression should look like this: 67-9 (5) +48/ 3x (7)-49. Step 3. Now we multiply and divide all the stuff together so first we do 48/3, which is 16. Then we multiply what is needed, in this case it is 3x7, which is 21. Are you following me so far? Excellent if not then read it over.
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