Flu Shot Case Study

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1. Using Stat Crunch, calculate the chi-square statistic and degrees of freedom for the following set of data for 300 people: Group A Group B Group C Total Had flu shot 20 30 32 82 Didn’t have flu shot 80 70 68 218 Total 100 100 100 300 Cell format Count (Percent with flu shot) (Percent of Group) (Percent of total) (Expected count) Got the Flu Shot? Group A Group B Group C Total Yes Percent with flu shot Percent with in group Percent of total Expected Count 20 (24.39%) (20%) (6.67%) (27.33) 30 (36.59%) (30%) (10%) (27.33) 32 (39.02%) (32%) (10.67%) (27.33) 82 (100%) (27.33%) (27.33%) No Percent without flu shot Percent with in group Percent of total …show more content…

No, the value of 4.1620049 was nonsignificant based on the level of significance for df2 which is 5.99. 2. Write a paragraph summarizing the results of the analysis in Exercise 1. In this analysis the null hypothesis is that the variable are independent, in other words whether or not a person has gotten their flu shot is unrelated to which group they are in. The Alternate hypothesis is that whether or not a person has gotten their flu shot is related to which group they were placed in, the variables are not independent. The results of this analysis are that the chi-square value is 4.1620049, which is nonsignificant according to the table on page 416 of the text which shows that the level of significance for 2 degrees of freedom is 5.99. The p value of 0.1248 is also indicative of a nonsignificant result. Based on the results of this analysis and the resulting significance the keep the null hypothesis. 3. Using StatCrunch, calculate the chi-square statistic and degrees of freedom for the following set of data for 180 people undergoing a knee replacement treatment with a drug

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