Investigating Heat Loss From a Container


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Investigating Heat Loss From a Container

Planning

We are investigating heat loss from a container and how it is
affected.

We could change:

Room temperature

Surface area

Amount of water

Use a lid

Insulate around it

Colour of tin

We could measure / observe:

Amount of time

Temperature

We will change:

Surface area

We will measure / observe:

Temperature (every minute for 5 minutes)

Our question is:

Does surface area effect the rate of heat loss?

We will keep these the same:

Colour of tin

Room temperature

Amount of water

Use a lid

Insulate around it



Preliminary investigation
=========================

Plan

1. Collect 4 different sized beakers

2. Boil some water in the kettle

3. Pour 50ml into each beaker

4. After 1 minute check temperature

5. Repeat step 4 after another minute continue this for 5 minutes

Beaker

Start

1

2

3

4

5

Temperature change

1

59°c

57°c

56°c

55°c

52°c

50°c

-9°c

2

72°c

71°c

66°c

63°c

60°c

57°c

-15°c

3

86°c

71°c

64°c

58°c

56°c

52°c

-34°c

4

72°c

68°c

65°c

60°c

57°c

53°c

-19°c


Main Investigation
------------------


Aim

To find out weather a beaker with a larger surface area cools quicker
than one with a smaller surface area.


Fair test

To make it a fair test we will keep the following the same:

Colour of tin - we will use clear beakers

Amount of water - we will use 100ml

How to Cite this Page

MLA Citation:
"Investigating Heat Loss From a Container." 123HelpMe.com. 24 Mar 2017
    <http://www.123HelpMe.com/view.asp?id=122040>.

Related Searches




123helpme.com/search.asp?text=boiling+water">boiling water in each beaker

Insulation - we will make sure the beakers are all the same thickness

Room temperature - we will do all the experiments at the same time in
the same room

Lid - we will not use lids on any of our beakers


Variables

We will measure 100ml boiling water into each beaker. The variable we
will change is the surface area.


Findings of preliminary work

In our main experiment we will make sure we label each beaker and
measure the surface area of each beaker


Prediction

I think the beaker with the largest surface are will cool quicker
because there is more surface exposed to the air which will make it
cool faster. The beaker with the smallest surface area will cool the
slowest because there is less of the surface exposed to the air which
would cool it faster.


Apparatus

3 beakers

Thermometer

Stopwatch

Kettle

Water


Method

1. Collect apparatus

2. Boil water in kettle

3. Pour 100ml boiling water into 1 of the beakers

4. Measure the start temperature

5. Measure again after:

1 minute

2 minutes

3minutes

4 minutes

5 minutes

6. we repeated this with two other beakers of water

7. we calculated the temperature change for each beaker

8. we will use the results to calculate which beaker cools the fastest


Results

Beaker

Start

1

2

3

4

5

Temperature change

1

75°c

73°c

71°c

69°c

67°c

65°c

- 10°c

2

78°c

74°c

71°c

68°c

65°c

62°c

- 16°c

3

72°c

64°c

58°c

54°c

50°c

48°c

- 24°c


Surface Areas

Beaker 1 - 16cm3

Beaker 2 - 22cm3

Beaker 3 - 36cm3


Conclusion

We found out that a larger surface area looses heat the fastest. The
bigger the surface area the bigger the drop in temperature. This
proves our prediction was correct.

There is a clear pattern in our results as the temperature decrease is
steady and there are no inaccurate results.

Evaluation

The method we used was good as it was simple and we did not get any of
the beakers mixed up.

If we had planned the experiment better we would have measured the
temperature every 2 minutes for 10 minutes rather than every minute
for only 5 minutes this would have hopefully given more accurate
results. Another way we could have got more accurate results is to do
the experiment again to compare the results.


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