In the lab the reaction that took place was a synthesis reaction. A synthesis reaction, is a type of chemical reaction in which two or more simple substances combine to form a new product. The reactants may be elements or compounds. In this case it is a gas and a metal that will react and produce a compound. The general form of a synthesis reaction is, A + B → AB. In order for this lab to be done successful you need knowledge on, percent composition, the empirical and molecular formula, the law of conservation of mass, moles and molar mass, qualitative and quantitative. To begin, the percent composition of a compound is the percent of the total mass that each element has in that compound. Every compound would have a certain percent composition. To calculate percent composition of a compound, you would have to determine the total molecular mass of the compound. For example, for H2O the total molar mass would be 18.00g/mol. You would then input the mass of one of the elements and the molar pass into the equation % by weight (mass) of element = (total mass of element present ÷ total mass of compound) x 100 to find out the percent composition. So for Oxygen it would be, % of O = (16.00g ÷ 18.00g/mol) x 100 which would equal 88.9%. Therefore the percent composition of O in this compound is roughly 88.9%. Furthermore, the molecular formula is the number and types of atoms that are existing in a single molecule of a substance. The empirical formula also known as the simplest formula is the ratio of elements present in the compound. The key difference between these two is that the empirical formula shows the simplest positive integer ratio of atoms of each element present in a compound whereas the molecular formula of a compound is a way ...
... middle of paper ...
...arbon. A mole of water would have the molar mass of 18g/mol (H2O Molar Mass: (1.008x2) + 16.00 = 18.016g/mol). Additionally, The law of conservation of mass was first established in 1789 by a French chemist name Antoine Lavoisier. The law states that mass is neither created nor destroyed in any ordinary chemical reaction. Or more simply, the mass of substances produced (products) by a chemical reaction is always equal to the mass of the reacting substances (reactants). E.g., 1.00g carbon + 5.34g sulphur = 6.34g carbon disulphide. In any chemical reaction the mass of things produced will be the same like the reactant it used. Mass of things reacted equals mass of things produced. So if you react 1 kg of stuff, the result will also be 1 kg of stuff. The materials do not "disappear" nor are other materials “created". This applies as mass cannot be created nor destroyed.
2-ethyl-1,3-hexanediol. The molecular weight of this compound is 146.2g/mol. It is converted into 2-ethyl-1-hydroxyhexan-3-one. This compounds molecular weight is 144.2g/mol. This gives a theoretical yield of .63 grams. My actual yield was .42 grams. Therefore, my percent yield was 67%. This was one of my highest yields yet. I felt that this was a good yield because part of this experiment is an equilibrium reaction. Hypochlorite must be used in excess to push the reaction to the right. Also, there were better ways to do this experiment where higher yields could have been produced. For example PCC could have been used. However, because of its toxic properties, its use is restricted. The purpose of this experiment was to determine which of the 3 compounds was formed from the starting material. The third compound was the oxidation of both alcohols. This could not have been my product because of the results of my IR. I had a broad large absorption is the range of 3200 to 3500 wavenumbers. This indicates the presence of an alcohol. If my compound had been fully oxidized then there would be no such alcohol present. Also, because of my IR, I know that my compound was one of the other 2 compounds because of the strong sharp absorption at 1705 wavenumbers. This indicates the presence of a carbonyl. Also, my 2,4-DNP test was positive. Therefore I had to prove which of the two compounds my final product was. The first was the oxidation of the primary alcohol, forming an aldehyde and a secondary alcohol. This could not have been my product because the Tollen’s test. My test was negative indicating no such aldehyde. Also, the textbook states that aldehydes show 2 characteristic absorption’s in the range of 2720-2820 wavenumbers. No such absorption’s were present in my sample. Therefore my final product was the oxidation of the secondary alcohol. My final product had a primary alcohol and a secondary ketone
In her essay, “The Fourth State of Matter”, Jo Ann Beard ruminates over the idea of plasma as a state of matter while dealing with the disintegration of her marriage, the death of her dog, and the violent deaths of her friend and colleagues. The tone, dialogue, and reflections in her essay mirror the detached bewilderment Beard feels while trying to make sense of the loss around her.
To complete this lab several chemicals must be measured and transferred to test tubes. First 5.0 mL of 0.200 M Fe(NO3)3 must be diluted to a total volume of 50 mL in a flask. Next 0.0020 M SCN–. This solution is then added to 4 test tubes in 1 mm increments. Each test tube is then put in to
The mass of Mg + the mass of O2=mass of MgxOx. Knowing the mass of
For the Identification of a Volatile Liquid Data Analysis I had the unknown number A53826. There are many ways that I used to determine the identification of the liquid. Some characteristics of the liquid that will help further in my research are that the liquid was colorless with a harsh strong odor. Before I did my research there were many components I did to help with my research. I first started by performing an experiment that helped determine the mass of my sample. The mass of my sample is one of the key components that will help me determine the moles of my sample. By using the ideal gas law (PV=nRT to n= (PV)/RT) using the mass of my sample in grams, the temperature of my sample after it evaporated during the double-boiling lab, the atmospheric pressure in the room using a barometer, and the volume of the flask I found the moles of the sample (approximately 0.00530 moles). Using the moles I found the molecular weight (mass of sample/ moles of sample). The average molecular weight was 94.9 g/mol. I first started my research by calculating the empirical formula by doing a combustion analysis for 2.0000 grams of my sample unknown (CxHyCLz) yielding 1.7787 grams of carbon dioxide and 0.7294 grams of water. By finding grams of carbon from the amount of grams in carbon dioxide, and finding grams of hydrogen from the amount of grams in water I added the two together (grams of carbon and hydrogen) and then subtracting it from 2.0000 grams of the sample to get my grams of chloride. I then converted the grams to moles and divided it by the smallest amount of mole ratio to get my empirical formula, CH_2 Cl. By using the empirical formula mass, 49.477 grams, and the molecular weight of my sample, 94.9 g/mol, I was able to find my mol...
... while weighing the reactants would try and avoid letting the reagents get in contact with apparatus that may not be necessary so as to avoid loss of some the substance and this way the exact mass would be achieved.
Mass of O = Mass of crucible, cover, KClO3 and MnO2 after heating (Step # 11) - Mass of crucible, cover, KClO3 and MnO2 before heating (Step # 5)
For this experiment we have to use physical methods to separate the reaction mixture from the liquid. The physical methods that were used are filtration and evaporation. Filtration is the separation of a solid from a liquid by passing the liquid through a porous material, such as filter paper. Evaporation is when you place the residue and the damp filter paper into a drying oven to draw moisture from it by heating it and leaving only the dry solid portion behind (Lab Guide pg. 33.).
One possible source of experimental error could be not having a solid measurement of magnesium hydroxide nor citric acid. This is because we were told to measure out between 5.6g-5.8g for magnesium hydroxide and 14g-21g for citric acid. If accuracy measures how closely a measured value is to the accepted value and or true value, then accuracy may not have been an aspect that was achieved in this lab. Therefore, not having a solid precise measurement and accurate measurement was another source of experimental error.
Mass Pb(NO2)3/ MW Pb(NO3)2 to find the mass of SO4, which equaled 0.1394g, then plugged into the percentage was exactly 55.75% SO4. The begging of the experiment requested that the percentage of SO4 in their fertilizer sample be found and that is exactly what was accomplished by this experiment, and the outcome, demonstrating the ability of my group to preform the requested task presented by the
Law of Matter means “ The principle that in any closed system subjected to no external forces the mass is constant irrespective of its changes in form.”(Google.com) In Accordance to the law of conservation of matter, matter is not either created or destroyed so you'll need the same amount of atoms after the change. Anything that has mass or matter can not be destroyed or created and that’s that! A cigarette that is burning turns to ash as it is being smoked because of the puffs that is being taken from it the smoke from the cigarette is floating in the air.
Energy is an odd concept, it is something that is neither here nor there yet has a profound impact on everything, both organic and inorganic. However, energy surrounds us in more ways than is commonly believed; it is possible that matter is only a form of energy. In fact, according to Albert Einstein, matter and energy are different forms of the same thing (“Do Antimatter and Matter Destroy Each Other?”). Through analyzing the superposition of bosons (particles without mass) and fermions (particles with mass), transformations between energy and matter, the creation of mass, and the mass of energy, the existence of what humans consider to be matter will be questioned.
Stoichiometry is a chemical branch that studies amounts of substances that are involved in reactions. Stoichiometry will help you to find out how much of the mixture you will need, or how much you started with. The calculations of a stoichiometry problem depends on a balanced chemical equations. The factors of the balanced equations signifies the molar ratio (the number of moles of each reactant needed to form a certain numbers of moles of each product) of the reactants and products taking part in the reaction. From the atomic and molecular point of view the stoichiometry in a chemical reaction is very simple. For example, one mole of oxygen reacts with two moles of hydrogen,
Matter is defined as anything that occupies space and can be perceived by one or more senses; a physical body, a physical substance, or the universe as a whole. There are four distinct states of matter: solids, liquids, gases, and plasma. There are other states of matter such as Bose-Einstein condesates and neutron degenerate matter, but those states can only be found under extreme conditions.