Purpose Of A Compound Lab Report

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Purpose of A Compound Purpose i) To determine what happens to the mass when the compound magnesium oxide is formed from the elements magnesium (Mg) and oxygen. To determine the ratio by mass of the magnesium and the oxygen in the compound magnesium oxide. Hypothesis When heated the mass should increase due to the introduction of oxygen to the magnesium. The predicted ratio of magnesium and oxygen will be 3:2 (3 parts magnesium, 2 parts oxygen). Materials Equipment Chemicals Retort Rod Magnesium Ribbon Retort Base Ring Clamp Clay Triangle Tongs Bunsen Burner Crucible Flint Lighter Safety Goggles Procedure Set up all equipment as demonstrated. Mass the crucible. Mass the crucible and the piece of magnesium. Calculate the …show more content…

Yes, the possibility of defying a Law of Chemistry was present during out lab. This is believed because the mass of the magnesium was smaller than the compound created, magnesium oxide. Explain the change in mass that occurred in the formation of magnesium oxide. In the formation of magnesium oxide a change in mass occurs due to the fact that oxygen has been introduced to the magnesium, making magnesium oxide. Since the oxygen and magnesium are chemically bonded it appears to be heavier then the initial weight of the magnesium. Is the formation of magnesium oxide a physical or chemical change? Why? The formation of magnesium oxide is a chemical change because two substances combined to form a new substance. Magnesium oxide is now a different substance then the magnesium at the beginning of the lab. The formation of chemical bonds allows the magnesium oxide to be a chemical process. 6. Calculate the experimental percent ratio by mass for magnesium and oxygen in magnesium oxide. The experimental ratio by mass for magnesium and oxygen in magnesium oxide would be 3:2. Mg- 24/40 = 60% O- 16/40 = 40% 60:40 = …show more content…

Calculate the actual percent ratio by mass for Mg and O in the compound MgO. Mg- .115/.14 = 82% O = 18% 82:18 Calculate the percent error between your experimental and actual percent rations by mass for: Mg- 82-60 x 100% = 36% 60 O- 18-40 x 100% =

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