Exploring Thermochromic Behavior of Cobalt Solutions

525 Words2 Pages

Project 6, Session 1 Pre-Lab Worksheet Your TA’s name: Dr. Sakamoto Your name: Andrew Fargalla Lab section: 5E Your email: andrewfargalla@email.arizona.edu GRADE ____ /10 p All work must be well-written and organized. If your penmanship is poor, you must type all responses. If you need to organize your thoughts, please use a separate sheet of paper. A major objective of this lab course is to develop skills in scientific communication. Just having the right “answer” is not good enough – you must communicate clearly and succinctly and use terms and concepts correctly. Question 1 (4 p) Task 1 concerns exploring the thermochromic behavior of cobalt isopropanol solutions (CoCl2(iPrOH)2) with methanol (MeOH). You are to prepare CoCl2(iPrOH)2/MeOH …show more content…

For these calculations assume the temperature remains constant at 25 °C. There are four steps here. First the initial concentration of CoCl2(iPrOH)2 needs to be determined. Second, the equilibrium concentration of CoCl2(iPrOH)2 must be found. Third is the calculation of the equilibrium concentration of CoCl2(MeOH)4, then fourth, the ratio [CoCl2(MeOH)4] / [CoCl2(iPrOH)2] at equilibrium. Show all work. Remember to state the equations you are using defining all variables and constants. Then substitute in the values and show the results. Be certain all sig figs and units are correct. You are expected to follow this format in all subsequent lab work without being prompted. The first thing to do is to find the initial concentration (C2) of cobalt isopropanol: C1V1=C2V2 0.0103 * 3 = C2 * 4 C2 = (0.0103M * 3mL)/(4mL) C2 = 0.0077 M Then find the equilibrium concentration (C3) of cobalt isopropanol using Beer’s law: Beer’s Law: A= lC3 C3 = A/l C3 = (0.705)/((319 cm-1M-1)(1 cm)) C3 = 0.0022 M The third step would be calculationg the equilibrium concentration (C4) of CoCl2(MeOH)4: C4 = C2-C3 C4 = 0.0077 M – 0.0022 M C4 = 0.0055

Open Document