Wait a second!
More handpicked essays just for you.
More handpicked essays just for you.
An essay on biosensors
Don’t take our word for it - see why 10 million students trust us with their essay needs.
Purpose: To identify an unknown microorganism by performing a series of biochemical tests on a pure bacterial culture. Materials and Methods: 1. Carbohydrate Utilization: Two culture tubes, phenol red lactose broth and phenol red sucrose broth, were each inoculated with one loopful of organism 3 from a broth culture. The broths were incubated at 37°C. After 24-48 hours, the mediums were examined. A positive test result is indicated by a change from the red broth to a yellow broth. A change from red broth to orange broth, or no change in color, is indicated as a negative result. A gas bubble produced in the Durham tube is indicated as a positive result for gas. A negative result for gas is indicated by no gas in the Durham tube. …show more content…
Casein Hydrolysis: The skim milk agar plate did not have any clearing around the growth. This is a negative test result. 8. Catalase Production: When 3% hydrogen peroxide was added to an isolated colony, no bubbles formed. This is a negative test result. Discussion: 1. Carbohydrate Utilization: The test result for the phenol red lactose broth was positive for acid and negative for gas. The positive result for the acid means that the organism is able to ferment the particular sugar lactose. The Durham tube did have gas in it which means the organism produced gas in the lactose broth. The rest result for the phenol red sucrose broth was negative for both acid and gas. This means the organism was not able to ferment in sucrose. The organism was also not able to produce gas in the sucrose broth. 2. Indole Production: The result for this test was negative. This means the organism does not produce tryptophanase. The organism is not able to split the amino acid tryptophan into indole and pyruvic acid. There was no indole produced from the breakdown of tryptophan. 3. Urea Hydrolysis: This test result was negative. There was no accumulation of sufficient ammonia from the hydrolysis of urea. An alkaline environment was not created by organism
One bacterium was gram negative. It underwent four different tests. These tests were the EMB test (Eosin Mehylene Blue), the Sulfur Indole Motility (SIM) test, the Urease test, and the Simmon’s Citrate Utilization test. The EMB test checks for a bacteria’s ability to ferment lactose. This test is accomplished by placing the bacteria on Eosin Methylene Blue agar. The agar is selective for gram negative bacteria and those bacteria that can ferment lactose will have colored growth, usually a metallic green sheen.
In order to learn even more about my specimen’s metabolic functions, I ran an experiment using a type of differential medium called litmus milk. This differential medium or any other type allows me to actually see certain changes that occur in the tubes after a certain metabolic reaction has taken place (Black, 2015). For this experiment two tubes that contain skin milk and the pH indicator, litmus were inoculated with specimens Ca and Cb. My first litmus milk tube was inoculated with a strain of specimen Ca that was taken from my specimen Ca glucose tube. While my second litmus milk tube contained a strain of specimen Cb that was taken from my specimen Cb lactose tube. After inoculation, both litmus milk tubes were put in an incubator at 37°C
The unknown substance is probably a carbohydrate because it tested positive for starch which is a polysaccharide. This reaction also had very similar results as the Lugol’s test for potatoes which is a polysaccharide. Although the colors from the test for potatoes were not the same colors as the test for the unknown; the Biuret test had a slight color change and the Lugol’s test had a dramatic color change for both the unknown and potatoes. I am sure that the unknown was a starch, but the Benedict’s test for sugar was positive for the potatoes while the Benedict’s test for the unknown didn’t have a color change. The unknown probably did not have a color change for the Benedict’s test simply because there were not enough sugar present in the unknown for it to test positive. The Sudan IV Test for Lipids did not test positive for the unknown nor the potatoes because there isn’t a trace of lipids in starch. Based on my results, the unknown has a little protein, a lot of starch and no traces of lipids or
I was given unknown organism #14, in order to find out what organism I had, I had to perform several different biochemical tests to identify it. Starting with the Gram stain test, which is performed to differentiate Gram-positive and Gram-negative cells. After staining, when observed through the microscope Gram-positive cells are a purple color with thick peptidoglycan cell walls. Gram-negative cells are a pinkish/red color with thinner cell walls. (handout G. s.) My organism was observed to be pinkish rod shaped meaning it is Gram-negative bacteria.
The purpose of this experiment was to discover the specificity of the enzyme lactase to a spec...
coli cells were grown at 37 degrees Celsius with calcium ions. These cells were then incubated in ice and placed into 4 polypropylene tubes. Each tube consisted of 25 microliters of E.coli cells. Two of the four were labeled with (+) while the other two were labeled (-). Positive was with samples that contained 100 pg/ microliter of pGLO, while negative was for the samples that did not. The 4 tubes were incubated in ice for 30 minutes, then heat shocked for 30 seconds at 42 degrees Celsius. The 4 tubes were then returned to the ice bath for 5 minutes. After the removal, .975 microliters of LB media was added to each tube at room temperature. The tubes were then shook at 225 RPM at 37 degrees Celsius for one hour. 300 microliters of cells were then extracted from the tubes and then placed in agar plates. The cells were spread across the plate and the incubated overnight at 37 degrees
Use the same plate from the TSA streak. Determine if catalase is produced through the break down of hydrogen peroxide. Proceed by adding reagent hydrogen peroxide and pay attention to bubbling. In other words, bubbling takes place due to breaking down hydrogen peroxide and the fabrication of oxygen gas (Benson, 2010). The control for this test is S. aureus.
To test this every 5 minutes the volume of gas in the test tube was observed and recorded until a period of 30 minutes had subsided. Such enzymes must remain in the required environment to properly carry out its tasks, if not then it becomes denatured and won’t carry out the correct functions. For example, the optimum temperature for enzymes in the human body is around 37oC. The issue begins at a chemical level in which the active site of the enzyme is altered because of the change in its environment.
I identified the genus and species of an unknown bacterial culture, #16, and I applied the following knowledge of morphologic, cultural and metabolic characteristics of the unknown microorganism according to the laboratory manual as well as my class notes and power point print outs. I was given an incubated agar slant labeled #16 and a rack of different tests to either examine or perform myself; the tests are as follows: Gram Stain; Nutrient Gelatin Test; Carbohydrate Fermentation; Dextrose, Lactose and Sucrose; IMVIC tests; Citrate, Indole, Mythel-Red and Vogues Proskauer test; as well as a Urease and TSI Test.
In the experiment, five periods are done to accomplish the goal of identification of the unknown microorganism. The first period aims to isolate the genomic DNA from the unknown microorganism using a
The purpose of the study is to identify an unknown microorganism using multiple microbiology lab techniques. Through this process I will gain knowledge on how to perform these techniques as well as the importance of these tests on identifying unknown microorganisms. This is significant as the goal of this course is to familiarize ourselves with the common microbiology tests as well as the microorganisms we encounter in our daily activities.
An error that occurred in the experiment was during the ceric nitrate test because solution 4 should have produced a color change. During a base hydrolysis of aspartame, aspartic acid, phenylalanine and methanol are produced, therefore the ceric nitrate test should have been a positive for alcohol. A reason that this could have shown a negative result is because methanol is a volatile substance and it could have evaporated out, which would have caused a negative ceric nitrate test
...ed that the liver was able to detoxify sulfate properly. The last inorganic constituent tested was calcium, which was done by adding equal amounts of urine and Sulkowitch’s reagent. A large amount of white precipitate was form due to the dietary consumption of the subject which can be that milk was consumed daily. Finally, the last tested was the abnormal constituents of urine. When testing for glucose the results were negative because the reagent was not reduced meaning that it did not turned greenish or red-brown color. The presence of glucose indicates diabetes mellitus which is a metabolic disorder that is caused by the usage of defective carbohydrate. Then when testing for albumin and globulin the results showed that a large amount of protein was present, which means that the subject had an abnormal leakiness or severe damage of the glomerular membrane or both.
...he results of the yogurt production after 3 days are as follows: the yogurt has a semi-solid texture, acidic smell, and a sour taste indicating that Lactic acid production took place. The wine production results after the same amount of time was as follows: the wine smells slightly of alcohol, the amount of liquid decreased, and some bubbling is still present; the balloon is currently inflated and producing carbon dioxide. Based on these results the ethanol fermentation was also successful. During both of these experiments fermentation took place, in the case of the yogurt the Lactic acid gave the yogurt a tart taste and smell, and in the Ethanol fermentation the wine smelled of alcohol and produced carbon dioxide indicated by the air in the balloon. In conclusion, NADH was oxidized and Lactic acid and ethanol were produced in both experiments through fermentation.
It was observed that the percentage titratable acidity increased, but not as higher as the value of treatment 1, because this treatment has already undergone alcoholic fermentation which was carried out by the added yeast, Saccharomyces cerevisiae. In this treatment, sugar was used as the substrate, and yeast was used to produced alcohol and carbon dioxide. Alcohol hinders the growth and survival of the unwanted microorganisms, since it denatures their membrane. In addition, alcoholic fermentation is used in making alcoholic beverages such as beer and wine. According to Rahman (2007), with respect to oxygen supply, this treatment undergone anaerobic fermentation because of the dissimilation of carbohydrate happened in which oxygen is not involved, but rather other substances, aldehydes and pyruvic acid that served as a hydrogen acceptor. On the other hand, increase in the percentage titratable acidity happened due to the molecules of carbon dioxide which has already reacted with the water, forming carbonic acid that made the mixture more acidic compared to the treatment 1. This happened since carbonic acid is a weak acid that causes a slight drop in pH, thus, making the mixture more acidic. Nevertheless, carbon dioxide alone is not acidic (Pederson,