I. Identifying an Unknown Compound Purpose/Problem: In this lab we had to figure out what our mystery compound was by performing two tests. One of the tests was called the Flame Test, which we use to find out the metal element in the compound. It is used to find the metal because each metal gives off its own unique flame color. The other test is called the Precipitate Test, which we use to find out the non-metal element in our compound by adding silver nitrate to it. It’s used to find the non-metal because each non-metal has its own unique reaction to silver nitrate. Conclusion: In this lab we had to figure out what our mystery compound was by performing two tests. One of the tests was called the Flame Test, which we use to find out the metal element in the compound. It is used to find the metal because each metal gives off its own unique flame color. The other test is called the Precipitate Test, which we use to find out the non-metal element in our compound by adding silver nitrate to it. It’s used to find the non-metal because each non-metal has its own unique reaction to silver nitrate. I figured out that my unknown compound is SrNO3 (Strontium Nitrate). The metallic ion in this compound is Strontium (Sr). I figured this out in the flame test because I recorded that SrCl2 had an orange-red flame, and that’s also the same color flame that my unknown compound had. I knew that Strontium was the metal in that compound since it was said first in the formula, so I didn’t include Chloride. I knew that my non-metallic ion was Nitrate (NO3). I found this out after doing the precipitate test. I tested each known compound with silver nitrate as well as my unknown compound and found that it reacted by turning foggy, just like Sodium Nitrate. I saw in that formula that Nitrate was the non-metal since it was stated last, so I didn’t include Sodium.
The purpose of the Unknown White Compound Lab was to identify the unknown compound by performing several experiments. Conducting a solubility test, flame test, pH paper test, ion test, pH probe test, conductivity probe test, and synthesizing the compound will accurately identified the unknown compound. In order to narrow down the possible compounds, the solubility test was used to determine that the compound was soluble in water. Next, the flame test was used to compare the unknown compound to other known compounds such as potassium chloride, sodium chloride, and calcium carbonate. The flame test concluded that the cation in the unknown compound was potassium. Following, pH paper was used to determine the compound to be neutral and slightly
The technique used to narrow down the identity of unknown white compound were solubility test, pH test, flame test, and ion test. The first technique used to narrowed the properties of unknown white compound was using solubility test. To conduct solubility test, 0.25 gram of unknown white compound was dissolved in 100 mL of water. After carefully observing the change while string unknown white compound in water, the unknown white compound was soluble because it dissolved in water completely. Using bursen burner, matches and deionized water, flame test was conducted for unknown compound and it burned lilac color. Then compared the color of unknown white compound to other compound that were narrowed. The results of flame test for compounds that were narrowed down is shown in the following table. The pH test was conducted using litmus paper. 0.50 gram of unknown white compound was measured and dissolved in 10 mL of water in beaker. After dissolving, placed the litmus paper in solution and recorded the pH value of unknown compound which was neutral. Then compared the pH value of unknown white compound to compound that were narrow down. The pH result of the KCL, KNO3, NaCl, and K2SO4 is presented in the following table. The ion test was also conducted in order to make sure that the identity of unknown white compound was matched with the compound that were narrow down. After conducting the test, the result of unknown white compound which formed precipitate compared to KCl, KNO3,NaCl, and K2SO4. The results shown in the following
This specific lab will focus on the two main variants of Atomic Absorption Spectroscopy: flame AA spectroscopy, and spectroscopy using a graphite furnace. The lab will also introduce and teach how to deal with both systematic and random error when using Atomic Absorption Spectroscopy.
We obtained an unknown metal with an identification number (6) from the instructor. Make sure not to get fingerprints on the sample otherwise it will interfere with identifying the density of
A group of 8th graders had to figure out what was in a Mystery Mixture, but they had no idea what it was. There were nine different substances that they had to work with. The substances were Epsom Salt, Chalk, Washing Soda, Road Salt, Table Salt, Citric Acid, Sugar, Vitamin C, and Baking Soda. The group believes the mystery mixture was Citric Acid & Baking Soda.
Silver is an important elements in the Periodic table. Every element in the periodic table has a special symbol, and silvers special symbol is Ag. Silvers chemical symbol Ag is an abbreviation of the Latin word for silver. The Latin word comes from arguments a Sanskrit word that means shiny.
If a firework is mostly a green/blue color, what element do you think is in the firework? If a firework is mostly a green/blue color I would belive copper would be one of the elements that make it up. I would guess copper because when copper is burned it gives off a blueish color light.
An elements¡¦ reaction to certain substances may be predicted by its placement on the Periodic Table of Elements. Across a period, an element on the left will react with more vigor than one on the right, of the same period. Vertically, as elements are sectioned into groups, the reaction of each element increases as you move down in the same group. With this in mind, the reactions of the substances involved in this experiment may be hypothesized, observed, and validated.
Obtain a sample of metal that has been immersed in boiling water and place it in the cup of water.
The use of dissection in classrooms is able to expand the knowledge of students by giving them a hands-on approach to anatomy. Dissection is one topic that is highly debated among all people who question whether it’s an ethical thing to do. According to Webster’s Dictionary the definition of the word ‘ethical’ means morally right and good or pertaining to right and wrong. The line between right and wrong is often a very thin line and many people don’t know where one ends and the other begins. I believe that dissection is an ethical way to get students more involved in learning and can give students a better understanding of the anatomical and physiological make-up of a once living organism.
Identifying Five Unknown Chemicals I was given 5 unknown samples, which are sodium chloride, sodium thiosulfate, calcium carbonate, sodium bicarbonate and sodium nitrate and these samples are all white and solid. However, I don’t know which substance is which sample and I was only given some information about the physical and chemical properties of these substances. In order to identify the 5 unknown samples, knowing which sample is which substance, I have to carry out this experiment, finding out the chemical and physical properties of these samples. How can we identify five unknown chemical samples that seem to look the same?
Observations: Once the magnesium was in the crucible and was being heated by the Bunsen burner, it glowed for a brief time. It then caught fire before the lid was placed on top. When it came into contact with the oxygen, the magnesium started glowing extremely bright, and intensely white. The glow became orange after some time. The magnesium ribbon then turned white.
The electrons then emit a photon of light. The light for the corresponding wavelength is determined by specific energy level of the certain element, resulting in different colors to appear. Due to sodium’s photons, a yellow and orange light is projected. For the chloride anion tests, the silver salts found in the unknown compound were insoluble, because a mixture between sulfate and silver is insoluble according to the solubility rules; therefore, when mixed with nitric acid and with silver nitrate, a precipitate was formed. The anion would only be chloride if the other four tests proved to be negative. The sulfate anion test also proved positive, as a white precipitant was formed when the unknown substance was mixed with barium chloride and hydrogen chloride; the mixture between barium and sulfate is also insoluble according to the solubility rules. For the acetate, nitrate, and carbonate tests, the results came out negative because there was no definite chemical reaction with the
The labels have fallen off of two bottles thought to contain solid sodium chloride or solid sodium carbonate. Describe a simple experiment which would allow you to determine which bottle contains which solid.