Class Notes: Data Structures and Algorithms
Summer-C Semester 1999 - M WRF 2nd Period CSE/E119, Section 7344
Homework #2 -- Due Fri 28 May 1999 : 09.30am
* Question 1. Assume that an n-element array (vector) a contains distinct integers arranged in no particular order. Write an algorithm to find the value and location of (a) the mean of a and (b) the value v in a closest to the mean. Note: If v equals the mean, then v is the value closest to the mean.
Example. If a = (1,2,3,5,4,6,7,9), then the mean equals 37/8 = 4.625. The value 5, which is in the fourth location (i = 4), happens to be the value closest to the mean.
Answer:
FindMean(a : array [1..n] of int):
{ sum = 0; posmean = -1, posclose = -1
for i = 1 to n do:
sum = sum + a[i]
endfor
mean = float(sum) / n
mdif = 9E13
for i = 1 to n do:
dif = abs(a[i] - mean)
if (dif < mdif) then
if (dif = 0) then
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